Alkenes can be hydrated via the addition of borane to yield alcohols with non-Markovnikov regiochemistry. The boron atom is an electrophile and thus follows Markovnikov's rule in adding to the carbon containing the most hydrogens. Oxidation of the alkylborane with basic peroxide yields the product alcohol. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing Instructions OR OR RO-B-OH RO-B OR

Alkenes can be hydrated via the addition of borane to yield alcohols with non-Markovnikov regiochemistry. The boron atom is an electrophile and thus follows Markovnikov's rule in adding to the carbon containing the most hydrogens. Oxidation of the alkylborane with basic peroxide yields the product alcohol. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing Instructions OR OR RO-B-OH RO-B OR

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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ОН 1. H(OAc)2, На0 2. NABH4 .CH3 CH3 H2C H3C Acid-catalyzed addition of water to an alkene yields an alcohol with Markovnikov regiochemistry. The electrophilic H adds to the sp carbon with the most hydrogens to yield the most stable carbocation intermediate, which then adds water to give the product alcohol. Because a carbocation intermediate is formed, rearrangements can occur prior to the addition of water. To avoid the possibility of rearrangement and still give a Markovnikov alcohol, alkenes can instead be treated with mercury(II) acetate in aqueous THF and then subsequently reduced with sodium borohydride. This reaction proceeds through a cyclic mercurinium ion intermediate which cannot rearrange. Water adds to the cyclic intermediate at the most substituted carbon to give an organomercury alcohol. The reduction step with sodium borohydride is complex and involves radicals. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing…
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