Alice and Bob are using the ElGamal cipher with the parameters p = 53 and a = 2.Alice makes the mistake of using the same ephemeral key for two plaintexts, x1 and x2. The eavesdropper Eve suspects that x1 = 5. She sees the twociphertexts y1= 41 and y247 in transit; these are the encryptions of a1 and x2, respectively.a) What is the masking key kM?b) What is the plaintext x2?

Data given - . x1 = 5 y1 = 41 y2 = 47 p = 53

Alice and Bob are using the EIGamal cipher with the parameters p = 53 and a = 2. Alice makes the mistake of using the same ephemeral key for two plaintexts, x1 and x2. The eavesdropper Eve suspects that x = 5. She sees the two ciphertexts y1 = 41 and y2 = 47 in transit; these are the encryptions of x1 and x2, respectively. a) What is the masking key kM? b) What is the plaintext x2?

Alice and Bob are using the EIGamal cipher with the parameters p = 53 and a = 2. Alice makes the mistake of using the same ephemeral key for two plaintexts, x1 and x2. The eavesdropper Eve suspects that x = 5. She sees the two ciphertexts y1 = 41 and y2 = 47 in transit; these are the encryptions of x1 and x2, respectively. a) What is the masking key kM? b) What is the plaintext x2?

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

See similar textbooks

Similar questions

Are there references or prove to say that multiplying two points in the elliptic curve cryptography ECC is not allowed, as an example below? Multiply the public key PKA by a point (Z) on the ECC since these two parameters (the public key and the point) are both points on the ECC. C=C'©h(Z.PKA||T1) where z: is a point on the ECC.
Is it feasible to produce secret keys for use in cryptographic protocols on a desktop computer using software in such a safe way that they can be utilized, and is this something that is even achievable?
A government organization decides that in order to protect the communications it has with its international partners, encryption is necessary. In a discussion with its equivalents, it is decided to develop a proprietary cryptographic algorithm for the following reasons: Is this decision supported by any evidence. What dangers are being exposed?
I need program which will do below The text is encoded with a transposition cipher, as follows: the plaintext is written row-wise across six columns. The ciphertext is formed by reading out successive columns in an arbitrary order (which you must figure out to decipher the message). Hint:look for common pairs of letters, such as 'th'. i need a program. which will do it
Suppose your RSA public key is PK: {n, e} = {13861, 37}. Your friend sends you a ciphertext C = 9908. But unfortunately you have forgotten your private key, now you have to crack it yourself.a) Write down a possible condition of factors p and q.p= q=b) What is your private key SK: {d}?d=c) What is the plaintext of your friend’s message?The plaintext M =d) Suppose the plaintext M is a 12-digit number consisting of a prefix “19” and 1234567890. What is the corresponding ciphertext? Since M is greater than n, you only need to encrypt four digits at a time. Ignore redundant zeros. e.g., 0001 = 1. The result should contain three integers.The ciphertext C0 =
Dexter wants to set up his own public keys. He chooses p = 23 and q = 37 with e = 7. Answer the following using RSA cryptographic method: a) Encrypt the message ‘100’ and find the CIPHER number (C) to be sent. [5] C = Me mod pq b) Find the decryption key ‘d’. c) Now decrypt the message ‘10’ (this is the CIPHER message received). M = Cd mod pq.
Alice and Bob are using the ElGamal cipher with the parameters p = 199 and a = 3. Their parameters are small and we decide to crack the cipher. Suppose Alice is observed sending public ephemeral key k = 103 and Bob sends public key = 136. ß Alice is observed transmitting the ciphertext y = 68. a) What is the masking key km? b) What is the plaintext?
Please explain the problem in detail so that I can understand.
DO NOT COPY AND PASTE FROM CHEGG. YOU WILL GET A THUMBS DOWN
Use Additive Ciphers (which we call as shift or Caesar cipher too) to encrypt the following sentence, "Everything in the universe is within you". Consider your key to be 18.
The mathematical formalization of encryption and decryption. If the message space is {a, b, c, d, e} and the ciphertext space is {1,2, 3,4,5}.What is the size of the key space? Write a number.
Assume the cryptanalist has two pairs (x, y1) and (, y2) such that yl = DES(K, x) and y2 = DES(K,¤). Build a exhaustive key search which requires only 255 encryption to find out K. (This would be a slight improvement over the total number of 256 keys).