Note: The notation from this problem is from Understanding Cryptography by Paar and Pelzl. We conduct a known-plaintext attack against an LFSR. Through trial and error we have determined that the number of states is m = 4. The plaintext given by 01100101 = X0X1X2X3X4X5X6X7 when encrypted by the LFSR produced the ciphertext 10010100 = yoYı Y2 Y3 Y3 Y5 Y6 Y7 · What are the tap bits of the LFSR? Please enter your answer as unspaced binary digits (e.g. 0101 to represent Рз %3D 0, р2 3D1, рі —D 0, ро 3 1).
Note: The notation from this problem is from Understanding Cryptography by Paar and Pelzl. We conduct a known-plaintext attack against an LFSR. Through trial and error we have determined that the number of states is m = 4. The plaintext given by 01100101 = X0X1X2X3X4X5X6X7 when encrypted by the LFSR produced the ciphertext 10010100 = yoYı Y2 Y3 Y3 Y5 Y6 Y7 · What are the tap bits of the LFSR? Please enter your answer as unspaced binary digits (e.g. 0101 to represent Рз %3D 0, р2 3D1, рі —D 0, ро 3 1).
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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it cycles through all possible 2m − 1 states within the shift register except the state where all bits are zero), unless it contains all zeros, in which case it will never change.
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