Algorithm prefixAvg1(X): input: An n-element array X output: An n-element array A of numbers such that A[i] is the average of elements X[0], ..., X[i] 1 Declare and initialize array A 2 for i = 0 to n-1 do 3 a = 0 4 for j = 0 to i do a += X[j] 6 A[i] = a / (i+1) 7 return array A 5 Algorithm prefixAvg2(X): input: An n-element array X output: An n-element array A of numbers such that A[i] is the average of elements X[0], X[i] .... 1 Declare and initialize array A 2 a = 0 3 for i = 0 to n-1 do a += X[i] 5 A[i] = a / (i+1) 6 return array A 4 %3D

Computer Networking: A Top-Down Approach (7th Edition)
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Author:James Kurose, Keith Ross
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Chapter1: Computer Networks And The Internet
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1. Consider a problem of computing the prefix average of a sequence of numbers stored in an array P consisting of P integers. We want to compute an array P such that P is the average of P for P .

Consider the two algorithms related to the above problem. Answer the questions given below

 

Algorithm prefixAvg1(X):
input: An n-element array X
output: An n-element array A of numbers such that A[i] is the average of elements X[0], ..., X[i]
1 Declare and initialize array A
2 for i = 0 to n-1 do
a = 0
4 for j = 0 to i do
a += X[j]
6 A[i] = a / (i+1)
7 return array A
3
5
Algorithm prefixAvg2(X):
input: An n-element array X
output: An n-element array A of numbers such that A[i] is the average of elements X[0], ..., X[i]
1 Declare and initialize array A
2 a = 0
3 for i = 0 to n-1 do
a += X[i]
5 A[i] = a / (i+1)
6 return array A
4
Transcribed Image Text:Algorithm prefixAvg1(X): input: An n-element array X output: An n-element array A of numbers such that A[i] is the average of elements X[0], ..., X[i] 1 Declare and initialize array A 2 for i = 0 to n-1 do a = 0 4 for j = 0 to i do a += X[j] 6 A[i] = a / (i+1) 7 return array A 3 5 Algorithm prefixAvg2(X): input: An n-element array X output: An n-element array A of numbers such that A[i] is the average of elements X[0], ..., X[i] 1 Declare and initialize array A 2 a = 0 3 for i = 0 to n-1 do a += X[i] 5 A[i] = a / (i+1) 6 return array A 4
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