Aleslavid Gan ESIFIS 7.5 (continued) 8. f(x) = sin(x) c = = ₁ F(x)=sin(x) f(x) = cos(x) f(c) = f '(c) = = f'(x) = - Sin(x) ƒ^ ( ² ) = = √2/² f"(x) = -cos) f" (c) = -√² f"(x) = sin(x) f" (c) = √2 प WIGG 2 + √2/2² (× - - 2 × 5) ² - 2!
Aleslavid Gan ESIFIS 7.5 (continued) 8. f(x) = sin(x) c = = ₁ F(x)=sin(x) f(x) = cos(x) f(c) = f '(c) = = f'(x) = - Sin(x) ƒ^ ( ² ) = = √2/² f"(x) = -cos) f" (c) = -√² f"(x) = sin(x) f" (c) = √2 प WIGG 2 + √2/2² (× - - 2 × 5) ² - 2!
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Please solve this!!—> Use the definition to find a Taylor Series centered at c=pi/4 for f(x)=sin(x)
The solution I got is in the photo. Please explain where I went wrong:)
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