Use the differentiation property on the Taylor series for to obtain a series for (1-¹). (Hint: You may have to differentiate more than once)

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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**Problem Statement:**

Use the differentiation property on the Taylor series for \(\frac{1}{1-x}\) to obtain a series for \(\frac{1}{(1-x)^3}\).

*(Hint: You may have to differentiate more than once)*

---

In this problem, you are tasked with using the properties of differentiation on the Taylor series expansion of the function \(\frac{1}{1-x}\) to find the expansion for the function \(\frac{1}{(1-x)^3}\).

**Steps to Consider:**

1. **Identify the Taylor Series of \(\frac{1}{1-x}\):**
   The Taylor series of \(\frac{1}{1-x}\) is a geometric series: 
   \[
   \frac{1}{1-x} = 1 + x + x^2 + x^3 + \ldots
   \]

2. **Differentiate the Series:**
   To find the series for \(\frac{1}{(1-x)^n}\) where \(n > 1\), you’ll typically differentiate the series multiple times. In this case, you will differentiate it twice.

3. **Apply the Differentiation Property:**
   - Differentiate the series once to get the series for \(\frac{1}{(1-x)^2}\).
   - Differentiate the resulting series again to find the series for \(\frac{1}{(1-x)^3}\).

These steps will guide you through using calculus-based properties to transform a known series into a more complex one through differentiation.
Transcribed Image Text:**Problem Statement:** Use the differentiation property on the Taylor series for \(\frac{1}{1-x}\) to obtain a series for \(\frac{1}{(1-x)^3}\). *(Hint: You may have to differentiate more than once)* --- In this problem, you are tasked with using the properties of differentiation on the Taylor series expansion of the function \(\frac{1}{1-x}\) to find the expansion for the function \(\frac{1}{(1-x)^3}\). **Steps to Consider:** 1. **Identify the Taylor Series of \(\frac{1}{1-x}\):** The Taylor series of \(\frac{1}{1-x}\) is a geometric series: \[ \frac{1}{1-x} = 1 + x + x^2 + x^3 + \ldots \] 2. **Differentiate the Series:** To find the series for \(\frac{1}{(1-x)^n}\) where \(n > 1\), you’ll typically differentiate the series multiple times. In this case, you will differentiate it twice. 3. **Apply the Differentiation Property:** - Differentiate the series once to get the series for \(\frac{1}{(1-x)^2}\). - Differentiate the resulting series again to find the series for \(\frac{1}{(1-x)^3}\). These steps will guide you through using calculus-based properties to transform a known series into a more complex one through differentiation.
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