Air having a dry ball temperature of 30°C and a wet bulb temperature of 20°C is initially heated in a heater so that the dry ball temperature increases to 80°C. Then the air is passed through the pile of corn kernels to dry. The air that comes out of the corn kernels is at a dry bulb temperature of 55°C. Then this air is passed to the dehumidifier to reduce the RH to 10%. Draw the course of this process of changing the air on a psychrometric diagram. The airflow rate through the corn kernels pile and dehumidifier is 2.0 m / s and the cross-sectional diameter of the pile is 0.7 m. a. Determine the amount of water lost from the pile of corn kernels (in grams of water / second) = Answer (grams of water / second). b. Determine the amount of water lost from the air when passing through the dehumidifier (in grams of water / second) = Answer (grams of water / second)

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
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Air having a dry ball temperature of 30°C and a wet bulb temperature of 20°C is initially heated in a heater so that the dry ball temperature increases to 80°C. Then the air is passed through the pile of corn kernels to dry. The air that comes out of the corn kernels is at a dry bulb temperature of 55°C. Then this air is passed to the dehumidifier to reduce the RH to 10%. Draw the course of this process of changing the air on a psychrometric diagram. The airflow rate through the corn kernels pile and dehumidifier is 2.0 m / s and the cross-sectional diameter of the pile is 0.7 m.

a. Determine the amount of water lost from the pile of corn kernels (in grams of water / second) = Answer (grams of water / second).

b. Determine the amount of water lost from the air when passing through the dehumidifier (in grams of water / second) = Answer (grams of water / second)

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