AIF63 + 3e" --> Al + 6F" A steady current of 10 amperes is passed through an aluminum-production cell for 15 minutes. Which of the following is the correct expression for calculating the numb of grams of aluminum produced? (1 faraday = 96,500 coulombs) A. [(10) (15) (96,500)] / [(27) (60)] grams O B. ((10) (15) (27)) / [(60) (96,500)) grams O C. (10) (15) (60) (27))/ [(96,500) (3)) grams O D. (96,500) (27)] / [(10) (15) (60) (3)) grams
AIF63 + 3e" --> Al + 6F" A steady current of 10 amperes is passed through an aluminum-production cell for 15 minutes. Which of the following is the correct expression for calculating the numb of grams of aluminum produced? (1 faraday = 96,500 coulombs) A. [(10) (15) (96,500)] / [(27) (60)] grams O B. ((10) (15) (27)) / [(60) (96,500)) grams O C. (10) (15) (60) (27))/ [(96,500) (3)) grams O D. (96,500) (27)] / [(10) (15) (60) (3)) grams
Chemistry
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Chapter1: Chemical Foundations
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![AIF63 + 3e -> Al + 6F"
A steady current of 10 amperes is passed through an aluminum-production cell for 15 minutes. Which of the following is the correct expression for calculating the number
of grams of aluminum produced? (1 faraday = 96,500 coulombs)
A. [(10) (15) (96,500)] / [(27) (60)] grams
O B. [(10) (15) (27)] / [(60) (96,500)] grams
O C. [(10) (15) (60) (27)] / [(96,500) (3)] grams
O D. (96,500) (27)] / [(10) (15) (60) (3)) grams](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5fb1edcb-e378-4007-8f8b-0be0a89cb7b5%2Fa162dd63-2fa6-4c66-9aa9-d38f3b74766a%2Fztie58_processed.jpeg&w=3840&q=75)
Transcribed Image Text:AIF63 + 3e -> Al + 6F"
A steady current of 10 amperes is passed through an aluminum-production cell for 15 minutes. Which of the following is the correct expression for calculating the number
of grams of aluminum produced? (1 faraday = 96,500 coulombs)
A. [(10) (15) (96,500)] / [(27) (60)] grams
O B. [(10) (15) (27)] / [(60) (96,500)] grams
O C. [(10) (15) (60) (27)] / [(96,500) (3)] grams
O D. (96,500) (27)] / [(10) (15) (60) (3)) grams
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