After three iterations, the Jacobi method applied with initial approximation (0) .(0) .(0) = x3 = 0.1 to the system X1 + 3.x2 – x3 | 3.x1 – x2 = 5 x2 + 2.x3 = 1

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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What is x1, x2 and x3?

After three
iterations, the
Jacobi method
applied with
initial
approximation
(0)
= X2' =
.(0)
.(0)
= x3
= 0.1
to the system
x1 + 3.x2 – x3
3x1 – x2 = 5
x2 + 2x3 = 1
Transcribed Image Text:After three iterations, the Jacobi method applied with initial approximation (0) = X2' = .(0) .(0) = x3 = 0.1 to the system x1 + 3.x2 – x3 3x1 – x2 = 5 x2 + 2x3 = 1
.(0)
.(0)
= 12
.(0)
X3
= 0.1
to the system
xị + 3.x2 – x3
|
3.x1 – x2 = 5
X2 + 2.x3 =
1
(after it has been
re-arranged so that
it is strictly
diagonally
dominant), gives
the solution of the
system as
X1 = ..., x2
... and x3 =
...
Transcribed Image Text:.(0) .(0) = 12 .(0) X3 = 0.1 to the system xị + 3.x2 – x3 | 3.x1 – x2 = 5 X2 + 2.x3 = 1 (after it has been re-arranged so that it is strictly diagonally dominant), gives the solution of the system as X1 = ..., x2 ... and x3 = ...
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