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(a) Calculate P(1 < X < 2). (Round your answer to four decimal places.) 0.5756 X (b) Calculate P(X> 1.5). (Round your answer to four decimal places.) 0.4901 x (c) What is the 90th percentile of the distribution? (Round your answer to three decimal places.) 2.815 days (d) What are the mean and standard deviation of X? (Round your answers to three decimal places.) mean X days X days standard deviation 1.834 0.533

(a) Calculate P(1 < X < 2). (Round your answer to four decimal places.) 0.5756 X (b) Calculate P(X> 1.5). (Round your answer to four decimal places.) 0.4901 x (c) What is the 90th percentile of the distribution? (Round your answer to three decimal places.) 2.815 days (d) What are the mean and standard deviation of X? (Round your answers to three decimal places.) mean X days X days standard deviation 1.834 0.533

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Please find a, b, and d. DON'T FIND C ANYMORE.

Once an individual has been infected with a certain disease, let X represent the time (days) that elapses before the individual becomes infectious. An article proposes a Weibull distribution with a = 2.7, ß = 1.7, and y = 0.5. [Hint: The two- parameter Weibull distribution can be generalized by introducing a third parameter y, called a threshold or location parameter: replace x in the equation below, -¹e-(x/B)* f(x; a, ß) = α te Ba 0 mean x 20 by x - y and x ≥ 0 by x ≥ y.] (a) Calculate P(1 < X < 2). (Round your answer to four decimal places.) 0.5756 X x < 0 (b) Calculate P(X> 1.5). (Round your answer to four decimal places.) 0.4901 X (c) What is the 90th percentile of the distribution? (Round your answer to three decimal places.) 2.815 days 1.834 standard deviation 0.533 (d) What are the mean and standard deviation of X? (Round your answers to three decimal places.) X days X days
Transcribed Image Text:Once an individual has been infected with a certain disease, let X represent the time (days) that elapses before the individual becomes infectious. An article proposes a Weibull distribution with a = 2.7, ß = 1.7, and y = 0.5. [Hint: The two- parameter Weibull distribution can be generalized by introducing a third parameter y, called a threshold or location parameter: replace x in the equation below, -¹e-(x/B)* f(x; a, ß) = α te Ba 0 mean x 20 by x - y and x ≥ 0 by x ≥ y.] (a) Calculate P(1 < X < 2). (Round your answer to four decimal places.) 0.5756 X x < 0 (b) Calculate P(X> 1.5). (Round your answer to four decimal places.) 0.4901 X (c) What is the 90th percentile of the distribution? (Round your answer to three decimal places.) 2.815 days 1.834 standard deviation 0.533 (d) What are the mean and standard deviation of X? (Round your answers to three decimal places.) X days X days
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