**Problem Statement:** A uniform 43 kg scaffold of length 5.6 m is supported by two light cables. A 76.0 kg painter stands 1.0 m from the left end of the scaffold, and his painting equipment is 1.6 m from the right end. If the tension in the left cable is twice that in the right cable, find the tensions in the cables (in N) and the mass of the equipment (in kg). **Required:** 1. Tension in the left cable: ______ N 2. Tension in the right cable: ______ N 3. Mass of the equipment: ______ kg

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**Problem Statement:**

A uniform 43 kg scaffold of length 5.6 m is supported by two light cables. A 76.0 kg painter stands 1.0 m from the left end of the scaffold, and his painting equipment is 1.6 m from the right end. If the tension in the left cable is twice that in the right cable, find the tensions in the cables (in N) and the mass of the equipment (in kg).

**Required:**

1. Tension in the left cable: ______ N
2. Tension in the right cable: ______ N
3. Mass of the equipment: ______ kg
Transcribed Image Text:**Problem Statement:** A uniform 43 kg scaffold of length 5.6 m is supported by two light cables. A 76.0 kg painter stands 1.0 m from the left end of the scaffold, and his painting equipment is 1.6 m from the right end. If the tension in the left cable is twice that in the right cable, find the tensions in the cables (in N) and the mass of the equipment (in kg). **Required:** 1. Tension in the left cable: ______ N 2. Tension in the right cable: ______ N 3. Mass of the equipment: ______ kg
Expert Solution
Step 14

Torque about the left end

Trl-msgl2-mpgrp-megl-re=0Tr=gmsl2+mprp+mel-rel        1

Torque about the right end

Tll-msgl2-mpgl-rp-megre=0Tl=gmsl2+mpl-rp+merel        2

Step 2

Tension in the left cable is twice that of the tension in the right cable

2Tr=Tl2gmsl2+mprp+mel-rel=gmsl2+mpl-rp+merelmsl2+mp3rp-l+me2l-3re=0me=-msl2-mp3rp-l2l-3re

Step 3

Substitute

me=-43 kg5.6 m2-76.0 kg31.0 m-5.6 m25.6 m-31.6 m=12.06 kg12.1 kg

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