Additional Exercise 14.78 For the equation below: Mg(s) + 2 HCl(aq) MgC2(aq) + H2(8) (a) How many moles of hydrogen will be liberated from 139.8 mL of 2.46 M HCI reacting with an excess of magnesium? mol H2 the tolerance is +/-2% (b) How many liters of hydrogen gas (H2) measured at 33 °C and 748 torr will be obtained? L H2 the tolerance is +/-2%
Additional Exercise 14.78 For the equation below: Mg(s) + 2 HCl(aq) MgC2(aq) + H2(8) (a) How many moles of hydrogen will be liberated from 139.8 mL of 2.46 M HCI reacting with an excess of magnesium? mol H2 the tolerance is +/-2% (b) How many liters of hydrogen gas (H2) measured at 33 °C and 748 torr will be obtained? L H2 the tolerance is +/-2%
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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![### Additional Exercise 14.78
**For the equation below:**
\[ \text{Mg}(\text{s}) + 2 \text{HCl}(\text{aq}) \rightarrow \text{MgCl}_2(\text{aq}) + \text{H}_2(\text{g}) \]
(a) **How many moles of hydrogen will be liberated from 139.8 mL of 2.46 M HCl reacting with an excess of magnesium?**
\[ \_\_\_\_\_\_\_\_\_ \text{ mol H}_2 \]
*the tolerance is +/-2%*
(b) **How many liters of hydrogen gas (\(\text{H}_2\)) measured at 33 ºC and 748 torr will be obtained?**
\[ \_\_\_\_\_\_\_\_\_ \text{ L H}_2 \]
*the tolerance is +/-2%*
### Explanation:
1. **Balanced Chemical Reaction:**
The given chemical reaction is:
\[ \text{Mg}(\text{s}) + 2 \text{HCl}(\text{aq}) \rightarrow \text{MgCl}_2(\text{aq}) + \text{H}_2(\text{g}) \]
- This reaction indicates that one mole of magnesium reacts with two moles of hydrochloric acid to produce one mole of magnesium chloride and one mole of hydrogen gas.
2. **Concentration and Volume Relationship:**
- Molarity (M) is defined as moles of solute per liter of solution.
- To find the moles of \(\text{HCl}\), use the equation: \[ \text{Moles of HCl} = \text{Molarity} \times \text{Volume (in liters)} \]
3. **Ideal Gas Law:**
- To convert the moles of hydrogen gas to liters at the given temperature and pressure, use the ideal gas law: \[ PV = nRT \]
- Where \(P\) is the pressure (in atm), \(V\) is the volume (in L), \(n\) is the number of moles, \(R\) is the ideal gas constant (0.0821 L·atm/(K·mol)), and \(T\) is the temperature (in Kelvin).
For further study, students are encouraged to solve](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2f9e96de-8215-4532-a7d0-6f1fdf87f241%2F298d6e8c-ace7-4206-b22f-6df2f5abe959%2Fo5ww3m.png&w=3840&q=75)
Transcribed Image Text:### Additional Exercise 14.78
**For the equation below:**
\[ \text{Mg}(\text{s}) + 2 \text{HCl}(\text{aq}) \rightarrow \text{MgCl}_2(\text{aq}) + \text{H}_2(\text{g}) \]
(a) **How many moles of hydrogen will be liberated from 139.8 mL of 2.46 M HCl reacting with an excess of magnesium?**
\[ \_\_\_\_\_\_\_\_\_ \text{ mol H}_2 \]
*the tolerance is +/-2%*
(b) **How many liters of hydrogen gas (\(\text{H}_2\)) measured at 33 ºC and 748 torr will be obtained?**
\[ \_\_\_\_\_\_\_\_\_ \text{ L H}_2 \]
*the tolerance is +/-2%*
### Explanation:
1. **Balanced Chemical Reaction:**
The given chemical reaction is:
\[ \text{Mg}(\text{s}) + 2 \text{HCl}(\text{aq}) \rightarrow \text{MgCl}_2(\text{aq}) + \text{H}_2(\text{g}) \]
- This reaction indicates that one mole of magnesium reacts with two moles of hydrochloric acid to produce one mole of magnesium chloride and one mole of hydrogen gas.
2. **Concentration and Volume Relationship:**
- Molarity (M) is defined as moles of solute per liter of solution.
- To find the moles of \(\text{HCl}\), use the equation: \[ \text{Moles of HCl} = \text{Molarity} \times \text{Volume (in liters)} \]
3. **Ideal Gas Law:**
- To convert the moles of hydrogen gas to liters at the given temperature and pressure, use the ideal gas law: \[ PV = nRT \]
- Where \(P\) is the pressure (in atm), \(V\) is the volume (in L), \(n\) is the number of moles, \(R\) is the ideal gas constant (0.0821 L·atm/(K·mol)), and \(T\) is the temperature (in Kelvin).
For further study, students are encouraged to solve
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