Additional Exercise 14.78 For the equation below: Mg(s) + 2 HCl(aq) MgC2(aq) + H2(8) (a) How many moles of hydrogen will be liberated from 139.8 mL of 2.46 M HCI reacting with an excess of magnesium? mol H2 the tolerance is +/-2% (b) How many liters of hydrogen gas (H2) measured at 33 °C and 748 torr will be obtained? L H2 the tolerance is +/-2%

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### Additional Exercise 14.78

**For the equation below:**

\[ \text{Mg}(\text{s}) + 2 \text{HCl}(\text{aq}) \rightarrow \text{MgCl}_2(\text{aq}) + \text{H}_2(\text{g}) \]

(a) **How many moles of hydrogen will be liberated from 139.8 mL of 2.46 M HCl reacting with an excess of magnesium?**

\[ \_\_\_\_\_\_\_\_\_ \text{ mol H}_2 \]

*the tolerance is +/-2%*

(b) **How many liters of hydrogen gas (\(\text{H}_2\)) measured at 33 ºC and 748 torr will be obtained?**

\[ \_\_\_\_\_\_\_\_\_ \text{ L H}_2 \]

*the tolerance is +/-2%*

### Explanation:

1. **Balanced Chemical Reaction:**
   The given chemical reaction is:
   \[ \text{Mg}(\text{s}) + 2 \text{HCl}(\text{aq}) \rightarrow \text{MgCl}_2(\text{aq}) + \text{H}_2(\text{g}) \]
   - This reaction indicates that one mole of magnesium reacts with two moles of hydrochloric acid to produce one mole of magnesium chloride and one mole of hydrogen gas.
   
2. **Concentration and Volume Relationship:**
   - Molarity (M) is defined as moles of solute per liter of solution.
   - To find the moles of \(\text{HCl}\), use the equation: \[ \text{Moles of HCl} = \text{Molarity} \times \text{Volume (in liters)} \]
   
3. **Ideal Gas Law:**
   - To convert the moles of hydrogen gas to liters at the given temperature and pressure, use the ideal gas law: \[ PV = nRT \]
   - Where \(P\) is the pressure (in atm), \(V\) is the volume (in L), \(n\) is the number of moles, \(R\) is the ideal gas constant (0.0821 L·atm/(K·mol)), and \(T\) is the temperature (in Kelvin).

For further study, students are encouraged to solve
Transcribed Image Text:### Additional Exercise 14.78 **For the equation below:** \[ \text{Mg}(\text{s}) + 2 \text{HCl}(\text{aq}) \rightarrow \text{MgCl}_2(\text{aq}) + \text{H}_2(\text{g}) \] (a) **How many moles of hydrogen will be liberated from 139.8 mL of 2.46 M HCl reacting with an excess of magnesium?** \[ \_\_\_\_\_\_\_\_\_ \text{ mol H}_2 \] *the tolerance is +/-2%* (b) **How many liters of hydrogen gas (\(\text{H}_2\)) measured at 33 ºC and 748 torr will be obtained?** \[ \_\_\_\_\_\_\_\_\_ \text{ L H}_2 \] *the tolerance is +/-2%* ### Explanation: 1. **Balanced Chemical Reaction:** The given chemical reaction is: \[ \text{Mg}(\text{s}) + 2 \text{HCl}(\text{aq}) \rightarrow \text{MgCl}_2(\text{aq}) + \text{H}_2(\text{g}) \] - This reaction indicates that one mole of magnesium reacts with two moles of hydrochloric acid to produce one mole of magnesium chloride and one mole of hydrogen gas. 2. **Concentration and Volume Relationship:** - Molarity (M) is defined as moles of solute per liter of solution. - To find the moles of \(\text{HCl}\), use the equation: \[ \text{Moles of HCl} = \text{Molarity} \times \text{Volume (in liters)} \] 3. **Ideal Gas Law:** - To convert the moles of hydrogen gas to liters at the given temperature and pressure, use the ideal gas law: \[ PV = nRT \] - Where \(P\) is the pressure (in atm), \(V\) is the volume (in L), \(n\) is the number of moles, \(R\) is the ideal gas constant (0.0821 L·atm/(K·mol)), and \(T\) is the temperature (in Kelvin). For further study, students are encouraged to solve
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