Info you may need below: 1 N2 + 3H2 = 2NH3 Starting with 0.500 M N; and 0.800 M Hz, the resction is allowed toproceed until it resches equilibrium. The [NHa = 0.150 M at 250°C.Determine K for this reaction at this temperature.4.Start by filling in the ICE table with the Initial concentrations.Resction[N] (M)[H] (M)[NH) (M)Initial0.500 M0.800 MChange-3x+2xEquilibrium0.500 M0.800 M-3x+2xb)Next, fill in the Changes in the system, in terms of x, whichwill determined by the stoichiometry. Reactants are usedup (-) and products are formed (+).c)Next, write equilibrium expressions, in terms of initialconcentrations and the changes that occur (x).d)Solve for x from the information you have.2x=0.150 Mx=0.150 M/20.075 Me)Determine the equilibrium concentrations of N and Hz-[N:] = 0.500 M-x= 0.500 M - 0.075 M[N 0.425 M[H] = 0.800 M - 3x= 0.800 M - 3(0.075 M)= 0.800 M - 0.225 M[Hln=_0.575 M 5.Now, imagine that the volume of the container increases from 10.0 L to50.0 L. Initially, there will be the same number of moles of each of thegases that were present at equilibrium. However, they are now in a largervolume, so their cancentrations will change.a)Determine the new concentrations of N., He and NH..(N] =[H] =[NH.) =.Using these new Initlal concentrations, detemine the value of Q,the reaction quotientCompare Q to K. Which way will the reaction proceed, under thesenew experimental conditions?c)d)Compare the number of moles of gas on the reactant and productsides of the equation. Circle the correct answers in the statementbekow.Increasing the volume of the system shifts the equilibrium towardthe reactants / products, which has a larger / amaller number ofmoles of gas

Solution : Equilibrium concentration expression provides the ratio of the concentration of a…

50.0 L. Initially, there will be the same number of moles of each of the gases that were present at equilibrium. However, they are now in a larger volume, so their ooncentrations will change. a) Determine the new concentrations of N. H and NH. IN = INH. =. Using these new Initial concentrations, determine the value of Q. the reaction quotient b)

50.0 L. Initially, there will be the same number of moles of each of the gases that were present at equilibrium. However, they are now in a larger volume, so their ooncentrations will change. a) Determine the new concentrations of N. H and NH. IN = INH. =. Using these new Initial concentrations, determine the value of Q. the reaction quotient b)

Introductory Chemistry: A Foundation

9th Edition

ISBN:9781337399425

Author:Steven S. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Donald J. DeCoste

Chapter17: Equilibrium

Section: Chapter Questions

Problem 1ALQ: Consider an equilibrium mixture of four chemicals (A. B. C. and D. all gases) reacting in a closed...

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