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Which is the correct expression for K, for this reaction? WCI, (g) + 3 H2 (g) <--> W (s) + 6 HCI (g) O Kp = (PHC) / (PH2)3 !! O K, = (Pw) O K = (Pw) / (Pwci6) O Kp = (PHCI)/ (Pwci6) (PH2) %3D O Kp = (PHC) / (Pwci6) (P12)

Which is the correct expression for K, for this reaction? WCI, (g) + 3 H2 (g) <--> W (s) + 6 HCI (g) O Kp = (PHC) / (PH2)3 !! O K, = (Pw) O K = (Pw) / (Pwci6) O Kp = (PHCI)/ (Pwci6) (PH2) %3D O Kp = (PHC) / (Pwci6) (P12)

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question 6 Which is the correct expression for K, for this reaction? WCI, (g) + 3 H2 (g) <--> W (s) + 6 HCI (g) O Kp = (PHCI) / (PH2)3 %3D O Kp = (Pw) O K, = (Pw) / (Pwci6) O Kp = (PHC)/ (Pwci6) (P12) O K, = (PHC) / (Pwci6) (P12)
Transcribed Image Text:Question 6 Which is the correct expression for K, for this reaction? WCI, (g) + 3 H2 (g) <--> W (s) + 6 HCI (g) O Kp = (PHCI) / (PH2)3 %3D O Kp = (Pw) O K, = (Pw) / (Pwci6) O Kp = (PHC)/ (Pwci6) (P12) O K, = (PHC) / (Pwci6) (P12)
Expert Solution
Step 1

Equilibrium constant, Kp

The ratio of product of partial pressures of products to reactants raised to the suitable powers is defined as equilibrium constant Kp

In Kp expression only partial pressures of gases are represented. The partial pressures of Solids and liquids are taken as unity and are not included in Kp expression

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