Acetylene (C₂H₂) gas and oxygen (O₂) gas react to form carbon dioxide (CO₂) gas and water (H₂O) vapor. Suppose you have 13.0 mol of C₂H₂ and 9.0 mol of O, in a reactor. What would be the limiting reactant? Enter its chemical formula below. 0

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**Determining the Limiting Reactant**

**Chemical Reaction:**
Acetylene (\( \text{C}_2\text{H}_2 \)) gas and oxygen (\( \text{O}_2 \)) gas react to form carbon dioxide (\( \text{CO}_2 \)) gas and water (\( \text{H}_2\text{O} \)) vapor.

**Suppose:**
- You have 13.0 mol of \( \text{C}_2\text{H}_2 \).
- You have 9.0 mol of \( \text{O}_2 \) in a reactor.

**Question:**
What would be the limiting reactant? Enter its chemical formula below.

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Transcribed Image Text:**Determining the Limiting Reactant** **Chemical Reaction:** Acetylene (\( \text{C}_2\text{H}_2 \)) gas and oxygen (\( \text{O}_2 \)) gas react to form carbon dioxide (\( \text{CO}_2 \)) gas and water (\( \text{H}_2\text{O} \)) vapor. **Suppose:** - You have 13.0 mol of \( \text{C}_2\text{H}_2 \). - You have 9.0 mol of \( \text{O}_2 \) in a reactor. **Question:** What would be the limiting reactant? Enter its chemical formula below. **Input Box with Options:** - A large rectangular input box. - Inside are two square overlays, suggesting options or a selectable feature. - Buttons for submission: - An "X" mark, likely for clearing input. - A circular arrow, likely for resetting or refreshing the input.
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