Oxygen and carbon disulfide react to form carbon dioxide and sulfur dioxide, like this: 3 0,(9)+ CS,(9) - CO,(9)+2S0,(g) Use this chemical equation to answer the questions in the table below. None. Suppose 80.0 mmol of O, and 26.7 mmol of CS, are added to an Some, but less than 80.0 mmol. 80.0 mmol. empty flask. How much O, will be in the flask at equilibrium? More than 80.0 mmol. None. Suppose 240. mmol of CO, and 480. mmol of SO, are added to an O Some, but less than 720. mmol. O 720. mmol. empty flask. How much 0, will be in the flask at equilibrium? More than 720. mmol.

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Oxygen and carbon disulfide react to form carbon dioxide and sulfur dioxide, like this:
3 O2(g)+CS,(g) - CO,(g)+2SO,(g)
Use this chemical equation to answer the questions in the table below.
Suppose 80.0 mmol of O, and
ONone.
26.7 mmol of CS, are added to an
O Some, but less than 80.0 mmol.
80.0 mmol.
empty flask. How much O, will be in
the flask at equilibrium?
More than 80.0 mmol.
Suppose 240. mmol of CO, and
O None.
2.
480. mmol of SO, are added to an
Some, but less than 720. mmol.
© 720. mmol.
empty flask. How much O, will be in
the flask at equilibrium?
More than 720. mmol.
Continue
Transcribed Image Text:Oxygen and carbon disulfide react to form carbon dioxide and sulfur dioxide, like this: 3 O2(g)+CS,(g) - CO,(g)+2SO,(g) Use this chemical equation to answer the questions in the table below. Suppose 80.0 mmol of O, and ONone. 26.7 mmol of CS, are added to an O Some, but less than 80.0 mmol. 80.0 mmol. empty flask. How much O, will be in the flask at equilibrium? More than 80.0 mmol. Suppose 240. mmol of CO, and O None. 2. 480. mmol of SO, are added to an Some, but less than 720. mmol. © 720. mmol. empty flask. How much O, will be in the flask at equilibrium? More than 720. mmol. Continue
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