Acetylene burns in air according to the following equation. C2H2(g) + 5/2 02(g) → 2 CO2(g) + H20(g) AHºrxn = -1255.8 kJ Given that AH°; of CO2(g) = -393.5 kJ/mol and AHOF of H20(g) = -241.8 kJ/mol, what is AHº¢ of C2H2(g)?

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Acetylene burns in air according to the following equation.
C2H2(g) + 5/2 02(g) → 2 CO2(g) + H20(g) AH°,
rxn = -1255.8 k)
Given that AHO of CO2(g) = -393.5 kJ/mol and AH°; of H20(g) = -241.8 kJ/mol, what is AHO, of C2H2(g)?
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Transcribed Image Text:Acetylene burns in air according to the following equation. C2H2(g) + 5/2 02(g) → 2 CO2(g) + H20(g) AH°, rxn = -1255.8 k) Given that AHO of CO2(g) = -393.5 kJ/mol and AH°; of H20(g) = -241.8 kJ/mol, what is AHO, of C2H2(g)? 4.0 Your response differs from the correct answer by more than 10%. Double check your calculations. kJ/mol Submit Answer
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