Acetic acid is a weak acid.  Its formula is CH3COOH.  Only the last H is an acid proton.  Vinegar is usually 5 % (v/v) acetic acid.  If 25.00 mL of vinegar is titrated by a standardized 0.9315 M NaOH solution, it takes 22.38 mL to reach the endpoint.  Calculate the molarity of acetic acid in the 5 % (v/v) vinegar.

Q: A student weighs out 0.9854 g of Na2CO3 unknown and dissolves it in 25.00 mL of deionized water. A…

A: Answer % of Na2CO3 in the unknown = 54.05% Formulas No.of moles                           = Given…

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A: HOOC-CH2-C-      COOH|   OH|CH2-COOH ( Citric acid )  Citric acid is tribasic acid and its n.factor…

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Q: You are titrating a 1.033 g sample of white vinegar solution (5.0% acetic acid) with a 1.00 M NaOH…

A: The reaction taking place in the titration is  CH3COOH + NaOH ----> CH3COONa + H2O Hence from the…

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A: Calculating moles of each solution Moles = M x Volume in L Moles = 0.75 M x 1.5 L Moles = 1.1 mole…

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A: Mass of KHP = 1.372 g Volume of sodium hydroxide, NaOH = 21.84 ml = 21.84 L1000

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Acid Base Titration

An acid-base titration is the method of quantitative analysis for determining the concentration of an acid and base by exactly neutralizing it with a standard solution of base or acid having known concentration.