A 40.0 mL solution of 0.100 mol/L acetic acid, CH3COOH (K, = 1.8 x 10), titrated with 0.100 mol/L sodium hydroxide at 25°C. Write the net ionic equation for this titration: NaOH + CH;COOH + CH;COON + H,0 NaOH + CH,COOH → CH;COONA + H,0 OH-+ CH,COOH → CH;COO- + H,0 OH- + CH,COOH → CH;COO + H,0 А. В. с. D. E. OH-+ H* > H20 F. OH-+ H* + H,0
A 40.0 mL solution of 0.100 mol/L acetic acid, CH3COOH (K, = 1.8 x 10), titrated with 0.100 mol/L sodium hydroxide at 25°C. Write the net ionic equation for this titration: NaOH + CH;COOH + CH;COON + H,0 NaOH + CH,COOH → CH;COONA + H,0 OH-+ CH,COOH → CH;COO- + H,0 OH- + CH,COOH → CH;COO + H,0 А. В. с. D. E. OH-+ H* > H20 F. OH-+ H* + H,0
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
![A 40.0 mL solution of 0.100 mol/L acetic acid, CH,COOH (K, = 1.8 x 10-5), is
titrated with 0.100 mol/L sodium hydroxide at 25 °C. Write the net ionic
equation for this titration:
%3D
NaOH + CH,COOH + CH,COONa + H,0
NaOH + CH,COOH > CH,COONa + H,0
OH- + CH,COOH
А.
В.
C.
+ CH,COO- + H20
OH-+ CH,COOH → CH;COO + H,0
OH + H* > H20
D.
Е.
F.
OH-+ H* + H,0](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0a39771c-7d6f-402c-adf6-1915f40dad39%2F2bddf820-e2f9-41f9-bcce-3bb1b10e4969%2Fmzdynu_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A 40.0 mL solution of 0.100 mol/L acetic acid, CH,COOH (K, = 1.8 x 10-5), is
titrated with 0.100 mol/L sodium hydroxide at 25 °C. Write the net ionic
equation for this titration:
%3D
NaOH + CH,COOH + CH,COONa + H,0
NaOH + CH,COOH > CH,COONa + H,0
OH- + CH,COOH
А.
В.
C.
+ CH,COO- + H20
OH-+ CH,COOH → CH;COO + H,0
OH + H* > H20
D.
Е.
F.
OH-+ H* + H,0
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