According to the figure below, wire section 1 of diameter D1 = 8 R and wire section 2 of diameter D2= 4R connected by a tapered section. The wire is copper, its resistivity uniformly distributed across any cross-section area through the wire's width. The electric potential change V along the length L = 4 m shown in section 2 is 20 µV. The number of charge carriers per unit volume is 8.49 x 1028 m3.What is the drift speed of the conduction electrons in section. 1.69 x 10-8 Qm and carriers a current. Assume that the current is

According to the figure below, wire section 1 of diameter D1 = 8 R and wire section 2 of diameter D2= 4R connected by a tapered section. The wire is copper, its resistivity uniformly distributed across any cross-section area through the wire's width. The electric potential change V along the length L = 4 m shown in section 2 is 20 µV. The number of charge carriers per unit volume is 8.49 x 1028 m3.What is the drift speed of the conduction electrons in section. 1.69 x 10-8 Qm and carriers a current. Assume that the current is

Electricity for Refrigeration, Heating, and Air Conditioning (MindTap Course List)

10th Edition

ISBN:9781337399128

Author:Russell E. Smith

Publisher:Russell E. Smith

Chapter12: Electronic Control Devices

Section: Chapter Questions

Problem 14RQ

See similar textbooks

Related questions

Q: 6. Consider 2 rectangular copper lines connected by a cylindrical via of resistance 2 N, as shown…

A: Resistance is defined as: R=ρlAWhere ρ is resistivity in Ωml is length of the conductor in mA is…

Q: Q) Two particles with positive charges, each 2.0 meters apart. The two charges of the particles have…

A: The solution can be achieved as follows.

Q: When dealing with a point charge what is the most logical place to set V=0? At the charge's outside…

A: Potential energy or electric potential is defined as the amount of electrical work done needed to…

Q: Q3) (i) Calculate the electrical conductivity of a piece of pure Si if it is given the number of…

A: Answer : 3 (i) : Given that ni=1×1010 cm3μe=1350 cm2.V-1.s-1μh=450 cm2.V-1.s-1T=300 K Although,…

Q: Describe the conductivity of a conductor and explain its conductivity In terms of the electrons In…

Q: Diagram of the problem, necessary formulas, clearance and numerical solution. A steady current of…

Question

According to the figure below, wire section 1 of diameter D1 = 8 R and wire section
2 of diameter D2= 4R connected by a tapered section. The wire is copper, its
resistivity = 1.69 x 10- 2m and carriers a current. Assume that the current is
uniformly distributed across any cross-section area through the wire's width. The
electric potential change V along the length L = 4 m shown in section 2 is 20 µV.
The number of charge carriers per unit volume is 8.49 x 1028 m3.What is the drift
speed of the conduction electrons in section.
Do
(2)
(1)

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step 3

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 3 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, electrical-engineering and related others by exploring similar questions and additional content below.

Similar questions

1- What are the various factors which affect Dielectric Strength?
An air gap has a length of 0.1 cm. What length of iron core has the same reluctance as the air gap? The relative permeability of the iron is 5000. Assume that the cross-sectional areas of the gap and the core are the same.
Question 1 A ferromagnetic core with a relative permeability of 1500 is shown in Figure 2. The dimensions are as shown in the diagram, and the depth of the core is 7 cm. The air gaps on the left and right sides of the core are 0.070 and 0.020 cm, respectively. Because of fringing effects, the effective area of the air gaps is 5 percent larger than their physical size. If there are 400 turns in the coil wrapped around the center leg of the core and if the current in the coil is 1.0 A, what is a) the flux in each of the left, center, and right legs of the core? b) the flux density in each air gap? 7 cm ст ст 30 cm 30 cm 7 cm 400 turns 0.05 cm 30 cm 0.07 cm 7 cm Core depth = 7 cm Figure 2
An iron core 0.4 m long and 5 cm2is wound with 300 turns. When a current of 0.5A flows in the coil, how much is the inductance of the coil. Assume the core has a permeability of 2500.
Please see the attached image.
Consider the large inductor in Figure 3 with given number of turns N, core permeability μ, core cross section area A, and core diameter are given. Note that the core length l is equal to π times the core diameter. Answer the questions and pick an answer from the given choices. The coil is made up of copper wire that has a cross section area of 1 cm2, and the length of each turn is nearly equal to 1 m. Find the resistance of the coil. (Assume an operating temperature of 20o C). 1) 180.2 mΩ 2) 17.2 mΩ 3) 1.2 Ω 4) 850.5 mΩ
At what temperature will intrinsic silicon become a conductor? Assume that un = 350 cm²/Vs and up = 60 cm²/Vs. The properties of silicon are as follows: B = 1.08 x 1031 K-3 cm-6, k = 8.62 x 10-5 eV/K, and EG = 1.12 eV. Hint: o≥1000(2-cm)-1 for a conductor typing format please
A ferromagnetic core in the shape of a doughnut has a cross-sectional area of 0.11 m2 and an average length of 1.4 m. The permeabil ity of the core is 1.206 × 10-3 Wb/A-t. m. Determine the reluctance of the magnetic circuit
A ferromagnetic core with a relative permeability of 1500 is shown in the Figure. The dimensions are shown in the diagram, and the depth of the core is 5cm. The air gaps on the left and right sides of the core are 0.050 and 0.070 cm, respectively. Because of the fringing effects, the effective area of the air gaps is 5 percent larger than their physical size. If there are 300 turns in the coil wrapped around the center leg of the core and if the current in the coil is 1.0 A, what are the flux values for the left, center, and right legs of the core? What is the magnetic field in each air gap? |7 cm 7 cm 7 cm to 30 cm 30 cm 7 cm 30 cm 0.07 cm 300 turns 0.05 cm 7 cm Core depth = 5 cm
A DC current I flows in a long solenoidwith n coil-turns per unit length. Thecore is made of iron with permeability µ , and has a cross section area S.Determine the force acting on the coreif it is withdrawn to the position shownin figure.
1.2 Magnetic Circuits The figure shows a ferromagnetic core whose mean path length is 40cm. There is a small gap of 0.05 cm in the structure of the otherwise whole core. The cross-sectional area of the core is 12 cm², the relative permeability of the core is 4000, and the coil of wire on the core has 400 turns. Assume that fringing in the air gap increases the effective cross-sectional area of the air gap by 5 percent. Mr = 4000 N=400 turns ·25.4m² Il=0.0005m A=0.0012 m² Given this information: a) Find the total reluctance of the flux path (iron plus air gap). b) Find the current required to produce a flux density of 0.5 T in the air gap. c) Qualitatively describe the effect of the air gap on the magnetic circuit.