Consider the large inductor in Figure 3 with given number of turns N, core permeability μ, core cross section area A, and core diameter are given. Note that the core length l is equal to π times the core diameter. Answer the questions and pick an answer from the given choices. The coil is made up of copper wire that has a cross section area of 1 cm2, and the length of each turn is nearly equal to 1 m. Find the resistance of the coil. (Assume an operating temperature of 20o C). 1) 180.2 mΩ 2) 17.2 mΩ 3) 1.2 Ω 4) 850.5 mΩ

Q: A ten-turn solenoid has a ferromagnetic core with a relative permeability of 10,000. The length of…

A: N=10 Permeability =10000 Length l =10cm Area A =1 cm2

Q: A 100-turn coil wound on a magnetic core is found to have an inductance of 200 mH. What inductance…

A: Given data, The value of number of turns N1 = 100. The value of number of turns N2 = 200. The value…

Q: Problem 1 A coil with an air core measures 3" in length with 300 turns of ½" diameter. Find the…

A:

Q: The resistance cylindrical core having 3 in diameter and 10 in height saturated 100 % with formation…

A: Given  Resistance 1 = 10 ohm  And resistance 2 = 85 ohm  We need to find the Water saturation of the…

Compensation Techniques

The compensation techniques are the methods that are employed in the electrical control systems to enhance the performance of the system. The performance are generally affected by the factors like lag in the compensating devices, slow response of the system of the components like sensors used in the control system. The basic compensation technique involves lag compensation, lead compensation or the combination of the both.