### Survey on Television Viewing Habits Among Young AmericansAccording to a survey, 58% of young Americans aged 18 to 29 say the primary way they watch television is through streaming services on the Internet. Suppose a random sample of 300 Americans from this age group is selected.#### Question:a. What percentage of the sample would we expect to watch television primarily through streaming services?---In the context of this survey, we would expect that 58% of the 300 young Americans sampled would watch television primarily through streaming services. To calculate this:\[ \text{Expected percentage} = \frac{58}{100} \times 300 \]\[ \text{Expected number} = 0.58 \times 300 = 174 \]So, we would expect approximately 174 out of 300 young Americans in the sample to use streaming services as their primary way of watching television.---This exercise aims to illustrate how percentages from survey data can be applied to estimate behaviors in a specific sample size. Understanding these applications helps in making predictions based on statistical data.

Sample size(n)=300sample proportion()=0.58

Answered: According to a survey, 58% of young…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A television station wishes to study the relationship between viewership of its 11 p.m. news program and viewer age (18 years or less, 19 to 35, 36 to 54, 55 or older). A sample of 250 television viewers in each age group is randomly selected, and the number who watch the station’s 11 p.m. news is found for each sample. The results are given in the table below. Age Group Watch11 p.m. News? 18 or less 19 to 35 36 to 54 55 or Older Total Yes 37 46 59 83 225 No 213 204 191 167 775 Total 250 250 250 250 1,000 (a) Let p1, p2, p3, and p4 be the proportions of all viewers in each age group who watch the station’s 11 p.m. news. If these proportions are equal, then whether a viewer watches the station’s 11 p.m. news is independent of the viewer’s age group. Therefore, we can test the null hypothesis H0 that p1, p2, p3, and p4 are equal by carrying out a chi-square test for independence. Perform this test by setting α = .05. (Round your answer to 3 decimal places.)…
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