According to a reputable magazine, 35% of people in a certain large country have sleepwalked at least once in their lives. Suppose a random sample of 200 people showed that 48 reported sleepwalking The null and alternative hypotheses for a test that would test whether the proportion of people who have sleepwalked is 0.35 are Ho p=0 35 and H, p# 0.35, respectively. The conditions for such a test are satisfied Use the technology output provided to determine the test statistic and p-value for the test, and provide a conclusion. Use a significance level of 0.05 Click the icon to view the technology output Determine the test statistic Z= (Round to two decimal places as needed) Determine the p-value p-value = (Round to three decimal places as needed.) !! What is the conclusion to this test? 0.35. Ho There sufficient evidence to conclude that the proportion of people who have sleepwalked

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### Sleepwalking Study: Proportion Hypothesis Test

According to a reputable magazine, 35% of people in a certain large country have sleepwalked at least once in their lives. Suppose a random sample of 200 people showed that 48 reported sleepwalking. The null and alternative hypotheses for a test that would test whether the proportion of people who have sleepwalked is 0.35 are \( H_0: p = 0.35 \) and \( H_A: p \neq 0.35 \), respectively. The conditions for such a test are satisfied. Use the technology output provided to determine the test statistic and p-value for the test, and provide a conclusion. Use a significance level of 0.05.

#### Hypothesis Test Details:

1. **Determine the Test Statistic**:  
   \( z = \) (Round to two decimal places as needed)

2. **Determine the p-value**:  
   \( \text{p-value} = \) (Round to three decimal places as needed)

3. **Conclusion**:  
   What is the conclusion to this test?  
   [Dropdown] \( H_0 \)  
   [Dropdown] sufficient evidence to conclude that the proportion of people who have sleepwalked [Dropdown] 0.35.

#### Technology Output

The technology output provides the following results:

- **Hypothesis Test Results**:
  - \( p \): Proportion of successes
  - \( H_0: p = 0.35 \)
  - \( H_A: p \neq 0.35 \)

- **Data**:
  - Proportion Count: 48
  - Total Sample: 200
  - Sample Proportion: 0.24
  - Standard Error (Std. Err.): 0.03372684
  - Z-Statistic (Z-Stat.): -3.2614970
  - P-value: 0.0011

Use this information to complete the hypothesis test.
Transcribed Image Text:### Sleepwalking Study: Proportion Hypothesis Test According to a reputable magazine, 35% of people in a certain large country have sleepwalked at least once in their lives. Suppose a random sample of 200 people showed that 48 reported sleepwalking. The null and alternative hypotheses for a test that would test whether the proportion of people who have sleepwalked is 0.35 are \( H_0: p = 0.35 \) and \( H_A: p \neq 0.35 \), respectively. The conditions for such a test are satisfied. Use the technology output provided to determine the test statistic and p-value for the test, and provide a conclusion. Use a significance level of 0.05. #### Hypothesis Test Details: 1. **Determine the Test Statistic**: \( z = \) (Round to two decimal places as needed) 2. **Determine the p-value**: \( \text{p-value} = \) (Round to three decimal places as needed) 3. **Conclusion**: What is the conclusion to this test? [Dropdown] \( H_0 \) [Dropdown] sufficient evidence to conclude that the proportion of people who have sleepwalked [Dropdown] 0.35. #### Technology Output The technology output provides the following results: - **Hypothesis Test Results**: - \( p \): Proportion of successes - \( H_0: p = 0.35 \) - \( H_A: p \neq 0.35 \) - **Data**: - Proportion Count: 48 - Total Sample: 200 - Sample Proportion: 0.24 - Standard Error (Std. Err.): 0.03372684 - Z-Statistic (Z-Stat.): -3.2614970 - P-value: 0.0011 Use this information to complete the hypothesis test.
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