According to a report, 52.3% of murders are committed with a firearm. (a) If 100 murders are randomly selected, how many would we expect to be committed with a firearm? (b) Would it be unusual to observe 56 murders by firearm in a random sample of 100 murders? Why? (a) We would expect to be committed with a firearm. (b) Choose the correct answer below. O A. No, because 56 is between u - 20 and u + 20. B. Yes, because 56 is greater than u + 20. C. No, because 56 is greater than u + 20. O D. No, because 56 is less than u - 20. E. Yes, because 56 is between u - 20 and u + 20.
According to a report, 52.3% of murders are committed with a firearm. (a) If 100 murders are randomly selected, how many would we expect to be committed with a firearm? (b) Would it be unusual to observe 56 murders by firearm in a random sample of 100 murders? Why? (a) We would expect to be committed with a firearm. (b) Choose the correct answer below. O A. No, because 56 is between u - 20 and u + 20. B. Yes, because 56 is greater than u + 20. C. No, because 56 is greater than u + 20. O D. No, because 56 is less than u - 20. E. Yes, because 56 is between u - 20 and u + 20.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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![**Text for Educational Website:**
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According to a report, 52.3% of murders are committed with a firearm.
**(a)** If 100 murders are randomly selected, how many would we expect to be committed with a firearm?
**(b)** Would it be unusual to observe 56 murders by firearm in a random sample of 100 murders? Why?
---
**(a)** We would expect [ ] to be committed with a firearm.
**(b)** Choose the correct answer below.
- **A.** No, because 56 is between μ - 2σ and μ + 2σ.
- **B.** Yes, because 56 is greater than μ + 2σ.
- **C.** No, because 56 is greater than μ + 2σ.
- **D.** No, because 56 is less than μ - 2σ.
- **E.** Yes, because 56 is between μ - 2σ and μ + 2σ.
---
**Explanation:**
- The question is focused on statistical analysis of a sample in relation to the population's average and standard deviation, represented by μ (mean) and σ (standard deviation).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa2a79f3c-9d5f-475d-8512-37c872933c1c%2Fd482da93-f202-43ab-a926-6ea41129ddd0%2F55zt79o_processed.png&w=3840&q=75)
Transcribed Image Text:**Text for Educational Website:**
---
According to a report, 52.3% of murders are committed with a firearm.
**(a)** If 100 murders are randomly selected, how many would we expect to be committed with a firearm?
**(b)** Would it be unusual to observe 56 murders by firearm in a random sample of 100 murders? Why?
---
**(a)** We would expect [ ] to be committed with a firearm.
**(b)** Choose the correct answer below.
- **A.** No, because 56 is between μ - 2σ and μ + 2σ.
- **B.** Yes, because 56 is greater than μ + 2σ.
- **C.** No, because 56 is greater than μ + 2σ.
- **D.** No, because 56 is less than μ - 2σ.
- **E.** Yes, because 56 is between μ - 2σ and μ + 2σ.
---
**Explanation:**
- The question is focused on statistical analysis of a sample in relation to the population's average and standard deviation, represented by μ (mean) and σ (standard deviation).
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