According to a report, 52.3% of murders are committed with a firearm. (a) If 100 murders are randomly selected, how many would we expect to be committed with a firearm? (b) Would it be unusual to observe 56 murders by firearm in a random sample of 100 murders? Why? (a) We would expect to be committed with a firearm. (b) Choose the correct answer below. O A. No, because 56 is between u - 20 and u + 20. B. Yes, because 56 is greater than u + 20. C. No, because 56 is greater than u + 20. O D. No, because 56 is less than u - 20. E. Yes, because 56 is between u - 20 and u + 20.

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**Text for Educational Website:**

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According to a report, 52.3% of murders are committed with a firearm. 

**(a)** If 100 murders are randomly selected, how many would we expect to be committed with a firearm?

**(b)** Would it be unusual to observe 56 murders by firearm in a random sample of 100 murders? Why?

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**(a)** We would expect [ ] to be committed with a firearm.

**(b)** Choose the correct answer below.

- **A.** No, because 56 is between μ - 2σ and μ + 2σ.
- **B.** Yes, because 56 is greater than μ + 2σ.
- **C.** No, because 56 is greater than μ + 2σ.
- **D.** No, because 56 is less than μ - 2σ.
- **E.** Yes, because 56 is between μ - 2σ and μ + 2σ.

--- 

**Explanation:**

- The question is focused on statistical analysis of a sample in relation to the population's average and standard deviation, represented by μ (mean) and σ (standard deviation).
Transcribed Image Text:**Text for Educational Website:** --- According to a report, 52.3% of murders are committed with a firearm. **(a)** If 100 murders are randomly selected, how many would we expect to be committed with a firearm? **(b)** Would it be unusual to observe 56 murders by firearm in a random sample of 100 murders? Why? --- **(a)** We would expect [ ] to be committed with a firearm. **(b)** Choose the correct answer below. - **A.** No, because 56 is between μ - 2σ and μ + 2σ. - **B.** Yes, because 56 is greater than μ + 2σ. - **C.** No, because 56 is greater than μ + 2σ. - **D.** No, because 56 is less than μ - 2σ. - **E.** Yes, because 56 is between μ - 2σ and μ + 2σ. --- **Explanation:** - The question is focused on statistical analysis of a sample in relation to the population's average and standard deviation, represented by μ (mean) and σ (standard deviation).
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