About 21 women in 100,000 have a certain disease (D), so P(D) = 0.00021 and P(no D) = 0.99979. The chance that atest will detect the disease when it is present is P(test pos|D) = 0.88. The chance that a test will detect the disease whenit is not present is P(test pos|no D) = 0.05. The probability that a randomly chosen woman who has this test will bothhave the disease AND test positive for it is 0.0001848; the probability that she will both be free of the disease and testpositive for it (a false positive) is 0.0499895. Complete parts a and b below.a. A test result was randomly chosen. The test result was positive. What is the probability that the woman who had thistest has the disease?(Type an integer or decimal rounded to four decimal places as needed.)

The provided information is as follows:The probability of having the disease is .The probability of…

Answered: About 21 women in 100,000 have a…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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