The Food Marketing Institute shows that 17% of households spend more than $100 per week on groceries. Assume the population proportion is p = 0.17 and a sample of 600 households will be selected from the population. Use z-table. Calculate (), the standard error of the proportion of households spending more than $100 per week on groceries (to 4 decimals). What is the probability that the sample proportion will be within +/- 0.02 of the population proportion (to 4 decimals)? What is the probability that the sample proportion will be within +/- 0.02 of the population proportion for a sample of 1,500 households (to 4 decimals)?

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A: Sample size n=140Population proportion p=0.71

Q: About 78​% of all female heart transplant patients will survive for at least 3 years. Ninety female…

A: Given information- Population proportion, p = 0.78 Sample size, n = 90 The sample proportion is- We…

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A: Given data,μ=180000σ=39000

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A: The given situation follows binomial distribution. The proportion of people born in United States…

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A: Given information- Population mean, µ = 570 hours Population variance, σ2 = 625 So, Population…

Q: Assume that the readings on thermometers are normally distributed with a mean of 0 degrees Celsius…

A: We have given that Mu= 0 , sigma =1 X~ N ( 0, 1) Zscore=(x-mu)/sigma

Q: About 75​% of all female heart transplant patients will survive for at least 3 years. Sixty female…

A: The population proportion, p=0.75 and sample proportion, p^=0.75. The sample of 60 female patients…

Q: Do I have to take many samples from my population to create a sampling distribution of the mean in…

A: Basics of sampling distribution of mean:The sampling distribution of the sample mean is essentially…

Q: The average number of pounds of red meat a person consumes each year is 196 with a standard…

A: We are given,μ = 196σ = 22n = 60

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Q: The manufacturer of cans of salmon that are supposed to have a net weight of 6 ounces tells you that…

A: GivenMean(μ)=6.04standard deviation(σ)=0.21Sample size(n)=33

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A:

Q: Find the probability that a single randomly selected salary that doesn't exceed 181000 dollars.…

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A:

Q: Find the probability that the mean for 20 randomly selected distances is greater than 195.70 cm.

A: Given that.   X~N( μ , ?)   μ=197.5     , ?=8.9   Z-score =( x - μ )/?

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.