A=Bonding electrons B= Sigma-bonds C =Nonbonding electron pairs D= Hybrid orbitals having nonbonding electron pairs E =Hybrid orbitals used F= 3-D structure (NAME) G =Polar (P) or nonpolar (NP) MOLECULE OR ION LEWIS STRUCTURE  A B C D E F G

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
icon
Related questions
Question

Given the following molecules and/or ions, characterize them according to the format
shown in the table below. The central atom of the molecule/ion is shown in boldface.
The central atom or molecules marked with an asterisk (*) do not obey the octet rule. 

 PCl5*

OF

SF4*

A=Bonding electrons
B= Sigma-bonds
C =Nonbonding electron pairs
D= Hybrid orbitals having
nonbonding electron pairs
E =Hybrid orbitals used
F= 3-D structure (NAME)
G =Polar (P) or nonpolar (NP)

MOLECULE OR ION LEWIS STRUCTURE  A B C D E F G
                 
Expert Solution
Step 1

PCl5 : It is a molecule.

Lewis structure is shown in image.

A = 10 (as there are 5 bonds and each bonds involves 2 electrons for formation)

B = 5 sigma bonds

C = There is no non-bonding electron pairs on central P atom 

D = NA 

E = Hybridization = No. of sigma bonds + l.p. = 5+0 = 5 = sp^3d 

F = It has steric factor 5. No l.p. is present. So, both geometry and shape are trigonal bipyramidal (TBP).

G = it is non-polar.

OF2 :

It is a molecule.

Lewis structure is shown in image.

A = 4 (as there are 2 bonds and each bonds involves 2 electrons for formation)

B = 2 sigma bonds

C = There is two non-bonding electron pairs on central O atom 

D = non-bonding electrons are present in sp^3 hybrid orbital.

E = Hybridization = No. of sigma bonds + l.p. = 2+2 = 4 = sp^3

F = It has steric factor 4. Two l.p. is present. So, its geometry is tetrahedral. and shape is bent (V-shaped).

G = it is polar.

SF4 :

It is a molecule.

Lewis structure is shown in image.

A = 8 (as there are 4 bonds and each bonds involves 2 electrons for formation)

B = 4 sigma bonds

C = There is 1 non-bonding electron pair on central S atom 

D = l.p. is present in sp^3d hybrid orbital.

E = Hybridization = No. of sigma bonds + l.p. = 4+1 = 5 = sp^3d 

F = It has steric factor 5. One l.p. is present. So, its geometry is Trigonal BiPyramidal TBP and shape is distorted Td or, see-saw.

G = it is polar.

 

steps

Step by step

Solved in 2 steps with 1 images

Blurred answer
Similar questions
Recommended textbooks for you
Chemistry
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry
Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education
Principles of Instrumental Analysis
Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning
Organic Chemistry
Organic Chemistry
Chemistry
ISBN:
9780078021558
Author:
Janice Gorzynski Smith Dr.
Publisher:
McGraw-Hill Education
Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
Chemistry
ISBN:
9781305079373
Author:
William L. Masterton, Cecile N. Hurley
Publisher:
Cengage Learning
Elementary Principles of Chemical Processes, Bind…
Elementary Principles of Chemical Processes, Bind…
Chemistry
ISBN:
9781118431221
Author:
Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:
WILEY