A+B AB Trial (A] (M) (e (M) Rate (M/) 0.200 0.200 2.00 x 10 0.400 0.200 8.00 x 102 0.200 0.400 4.00 x 10 What is the rate constant for the reaction above?

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Chapter1: Chemical Foundations
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The image presents a chemical reaction data table for the reaction \( \text{A} + \text{B} \rightarrow \text{AB} \).

**Table:**

| Trial | [A] (M) | [B] (M) | Rate (M/s)   |
|-------|---------|---------|--------------|
| 1     | 0.200   | 0.200   | \(2.00 \times 10^{-2}\) |
| 2     | 0.400   | 0.200   | \(8.00 \times 10^{-2}\) |
| 3     | 0.200   | 0.400   | \(4.00 \times 10^{-2}\) |

**Question:**
What is the rate constant for the reaction above?

This table is used to determine the rate constant by observing how changes in initial concentrations of reactants A and B affect the reaction rate.
Transcribed Image Text:The image presents a chemical reaction data table for the reaction \( \text{A} + \text{B} \rightarrow \text{AB} \). **Table:** | Trial | [A] (M) | [B] (M) | Rate (M/s) | |-------|---------|---------|--------------| | 1 | 0.200 | 0.200 | \(2.00 \times 10^{-2}\) | | 2 | 0.400 | 0.200 | \(8.00 \times 10^{-2}\) | | 3 | 0.200 | 0.400 | \(4.00 \times 10^{-2}\) | **Question:** What is the rate constant for the reaction above? This table is used to determine the rate constant by observing how changes in initial concentrations of reactants A and B affect the reaction rate.
Expert Solution
Step 1

Consider the following reaction:

A + B  AB

Let the order of the reaction with respect to A is α and the order of the reaction with respect to B is β. The rate law can be written as follows:

Rate=KAαBβ

Where, K is rate constant.

 

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