aa = nn = [] ii = ['1', 'o', '1', '1', '1', '1', 'o', '1', 'o', '1', '1'] while len(aa) > 0: if len(aa) > 3: gg = aa[len(aa) - 2] else: gg = aa[0] aa.remove(gg) %3D nn.append(gg) for mm in nn: ii.insert(3, mm) ii.pop(1) mm print(mm[len(mm)-5:1) '".join(ii) %3D

aa = nn = [] ii = ['1', 'o', '1', '1', '1', '1', 'o', '1', 'o', '1', '1'] while len(aa) > 0: if len(aa) > 3: gg = aa[len(aa) - 2] else: gg = aa[0] aa.remove(gg) %3D nn.append(gg) for mm in nn: ii.insert(3, mm) ii.pop(1) mm print(mm[len(mm)-5:1) '".join(ii) %3D

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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