rps (Exercise 5.26 from the textbook) Write a function rps that returns the result of a game of "Rock, Paper, Scissors". The function accepts two arguments, each one of 'R','P','s', that represents the symbol played by each of the two players. The function returns: • 1 if the first player wins • O if a tie • 1 if the second player wins • Scissors beats Paper beats Rock beats Scissors Sample usage: >>> rps('R','p') player 2 wins, return 1 >>> rps('R','s') # player 1 wins, return -1 -1 >>> rps('s','s') # tie, return 0 >>> [ (p1,p2, rps(pl,p2)) for p1 in 'RPS' for p2 in 'rPs'] [C'R', 'R', 0), ('R', 'P', 1), ('R', 's', -1), ('P', 'R', -1), ('p', 'p', 0), C'P', 's', 1), ('s', 'R', 1), ('s', 'P', -1), ('s', 's', 0)]
rps (Exercise 5.26 from the textbook) Write a function rps that returns the result of a game of "Rock, Paper, Scissors". The function accepts two arguments, each one of 'R','P','s', that represents the symbol played by each of the two players. The function returns: • 1 if the first player wins • O if a tie • 1 if the second player wins • Scissors beats Paper beats Rock beats Scissors Sample usage: >>> rps('R','p') player 2 wins, return 1 >>> rps('R','s') # player 1 wins, return -1 -1 >>> rps('s','s') # tie, return 0 >>> [ (p1,p2, rps(pl,p2)) for p1 in 'RPS' for p2 in 'rPs'] [C'R', 'R', 0), ('R', 'P', 1), ('R', 's', -1), ('P', 'R', -1), ('p', 'p', 0), C'P', 's', 1), ('s', 'R', 1), ('s', 'P', -1), ('s', 's', 0)]
Computer Networking: A Top-Down Approach (7th Edition)
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Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
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In Python IDLE: How would I write a function to solve the problem in the attached image?
![rps
(Exercise 5.26 from the textbook) Write a function rps that returns the result of a game of "Rock,
Paper, Scissors". The function accepts two arguments, each one of 'R','P','s', that represents
the symbol played by each of the two players. The function returns:
• 1 if the first player wins
• O if a tie
• 1 if the second player wins
• Scissors beats Paper beats Rock beats Scissors
Sample usage:
>>> rps('R','p') # player 2 wins, return 1
>>> rps('R','s') # player 1 wins, return -1
-1
>>> rps('s','s') # tie, return 0
>>> [ (p1,p2, rps(pl,p2)) for p1 in 'RPS' for p2 in 'RPS']
[C'R', 'R', 0), ('R', 'P', 1), ('R', 's', -1), ('P', 'R', -1), ('p', 'p', 0),
('P', 's', 1), ('s', 'R', 1), ('s', 'p', -1), ('s', 's', 0)]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc4b85f9b-2931-43f1-91f6-17c8a9947553%2F3703f37c-d5c7-4b19-9c68-70ae529f7c2f%2F1nruby8_processed.jpeg&w=3840&q=75)
Transcribed Image Text:rps
(Exercise 5.26 from the textbook) Write a function rps that returns the result of a game of "Rock,
Paper, Scissors". The function accepts two arguments, each one of 'R','P','s', that represents
the symbol played by each of the two players. The function returns:
• 1 if the first player wins
• O if a tie
• 1 if the second player wins
• Scissors beats Paper beats Rock beats Scissors
Sample usage:
>>> rps('R','p') # player 2 wins, return 1
>>> rps('R','s') # player 1 wins, return -1
-1
>>> rps('s','s') # tie, return 0
>>> [ (p1,p2, rps(pl,p2)) for p1 in 'RPS' for p2 in 'RPS']
[C'R', 'R', 0), ('R', 'P', 1), ('R', 's', -1), ('P', 'R', -1), ('p', 'p', 0),
('P', 's', 1), ('s', 'R', 1), ('s', 'p', -1), ('s', 's', 0)]
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