A 21186Rn nucleus undergoes alpha decay according to the reaction 21186Rn → 20784Po + 42He. Determine the following. (Let the atomic mass of 21186Rn be 210.9906 u, the atomic mass of 20784Po be 206.9816 u and the atomic mass of 42He be 4.0026 u.) (a)Q value (in MeV) for the process (Enter your answer to at least two decimal places.) (b)Kinetic energy (in MeV) of the alpha particle after the decay (Enter your answer to at least two decimal places.) (c) Kinetic energy (in MeV) of the daughter nucleus after the decay
A 21186Rn nucleus undergoes alpha decay according to the reaction 21186Rn → 20784Po + 42He. Determine the following. (Let the atomic mass of 21186Rn be 210.9906 u, the atomic mass of 20784Po be 206.9816 u and the atomic mass of 42He be 4.0026 u.) (a)Q value (in MeV) for the process (Enter your answer to at least two decimal places.) (b)Kinetic energy (in MeV) of the alpha particle after the decay (Enter your answer to at least two decimal places.) (c) Kinetic energy (in MeV) of the daughter nucleus after the decay
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A 21186Rn nucleus undergoes alpha decay according to the reaction 21186Rn → 20784Po + 42He. Determine the following. (Let the atomic mass of 21186Rn be 210.9906 u, the atomic mass of 20784Po be 206.9816 u and the atomic mass of 42He be 4.0026 u.)
(a)Q value (in MeV) for the process (Enter your answer to at least two decimal places.)
(b)Kinetic energy (in MeV) of the alpha particle after the decay (Enter your answer to at least two decimal places.)
(c) Kinetic energy (in MeV) of the daughter nucleus after the decay
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