TreatmentShamResearchers conducted a study to determine whether magnets are effective in treating back pain. The results are shown in the table forthe treatment (with magnets) group and the sham (or placebo) group. The results are a measure of reduction in back pain. Assume thatthe two samples are independent simple random samples selected from normally distributed populations, and do not assume that thepopulation standard deviations are equal. Complete parts (a) and (b) below.Ini28280.510.440.771.09a. Use a 0.05 significance level to test the claim that those treated with magnets have a greater mean reduction in pain than those given a sham treatment.What are the null and alternative hypotheses?O A. Ho: H1 H2O C. Ho: H1 * H2H1: H1

a. Use a 0.05 significance level to test the claim that those treated with magnets have a greater mean reduction in pain than those given a sham treatment. What are the null and alternative hypotheses? O A. Ho: H1 H2 OD. Ho: H1 = P2 OC. Ho: H1 + H2 H1: H1

a. Use a 0.05 significance level to test the claim that those treated with magnets have a greater mean reduction in pain than those given a sham treatment. What are the null and alternative hypotheses? O A. Ho: H1 H2 OD. Ho: H1 = P2 OC. Ho: H1 + H2 H1: H1

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

An article includes the accompanying data on compression strength (lb) for a sample of 12-oz aluminum cans filled with strawberry drink and another sample filled with cola. Beverage Sample Size Sample Mean Sample SD Strawberry Drink 10 535 24 Cola 10 559 15 Does the data suggest that the extra carbonation of cola results in a higher average compression strength? Base your answer on a P-value. (Use ? = 0.05.) State the relevant hypotheses. (Use ?1 for the strawberry drink and ?2 for the cola.) H0: ?1 − ?2 = 0Ha: ?1 − ?2 ≥ 0H0: ?1 − ?2 = 0Ha: ?1 − ?2 ≠ 0 H0: ?1 − ?2 = 0Ha: ?1 − ?2 < 0H0: ?1 − ?2 = 0Ha: ?1 − ?2 > 0 Calculate the test statistic and determine the P-value. (Round your test statistic to one decimal place and your P-value to three decimal places.) t = P-value = State the conclusion in the problem context. Reject H0. The data suggests that cola has a higher average compression strength than the strawberry drink.Reject H0. The…
Is a person's favorite pizza topping dependent on their gender? A random sample of pizzas ordered and the gender of the person who ordered were recorded and the results are found in the table below. Use this data to test whether or not pizza topping preference is independent of gender at the a = 0.05 level of significance. Which would be correct hypotheses for this test? Ho: 41 = H2; H1 : µ1 # µ2 |Ho: Pizza topping preference and gender are independent; H, : There is some relationship between a person's gender and their pizza topping preference O Họ: Pizza topping preference is dependent on gender; H,: Pizza topping preference and gender are independent O Ho : P1 = P2; H1:P1 # P2 Sample data: Cheese Pepperoni Sausage Mushroom Veggie Female 25 12 4 6 17 Male 24 13 20 2 Test Statistic (2 decimal places): Give the P-value (4 decimal places - if less than 0.001 answer 0): Which is the correct result: O Do not Reject the Null Hypothesis O Reject the Null Hypothesis Which would be the…
Assume a significance level of α = 0.05 and use the given information to complete parts (a) and (b) below. Original claim: Less than 52% of adults would erase all of their personal information online if they could. The hypothesis test results in a P-value of 0.1763. GECE I all the cause the value to its a cual C. Fail to reject Ho because the P-value is greater than a. OD. Reject Ho because the P-value is less than or equal to α. b. Without using technical terms, state a final conclusion that addresses the original claim. Which of the following is the correct conclusion? OA. There is sufficient evidence to support the claim that the percentage of adults that would erase all of their personal information online if they could is less than 52%. OB. There is not sufficient evidence to support the claim that the percentage of adults that would erase all of their personal information online if they could is less than 52%. OC. The percentage of adults that would erase all of their personal…
Many parents have turned to St. John's wort, an herbal remedy, to treat their children with attention deficit hyperactivity disorder (ADHD). The Journal of the American Medical Association (June 11, 2008) published an article that explored the herb's effectiveness. Children with ADHD were randomly assigned to take either St. John's wort capsules or placebos. The contingency table below broadly reflects the results found in the study. (You may find it useful to reference the appropriate table: chi-square table or F table) Effect on ADHD Treatment No Change in ADHD Improvement in ADHD St. John's wort 12 15 Placebo 14 13 At the 5% significance level, do the data indicate that St. John's wort affects children with ADHD? a. Choose the null and alternate hypotheses. O Ho: Effect on ADHD is independent of the treatment; HẠ: Effect on ADHD is dependent of the treatment O Ho: Effect on ADHD is dependent of the treatment; HA: Effect on ADHD is independent of the treatment b. Calculate the test…
The CEO of a popular company claims that the mean response time for customer service calls is 9 minutes. A group of recent customers believes that the mean response time is actually slower than that, meaning it takes more than 9 minutes. The customers wish to conduct a hypothesis test at the a = 0.05 level of significance to determine if their claim that it is slower is correct. Which would be correct hypotheses for such a test? Ho:u = 9, Hị: µ > 9 Ho:4 + 9, Hị: µ = 9 %3D OHo:H < 9, Hị :H = 9 ΘΗ :μ = 9, Η :μ <9 ΘΗ:μ = 9, Η :μέ9 What does the P-value measure? O The power of mind of the statistician who performed the statistical experiment O The probability that the alternate hypothesis is true The probability that the results of a statistical experiment are due only to chance O The probability that the results of an statistical experiment are due to something more significant than chance If the resulting P-value is 0.065, which would be the appropriate conclusion? There is significant…
Which of the following null hypotheses is appropriate for an independent-measures t test? Ho Pi = P2 H = 0 H μ#6.
1. Calculate r2 2. Interpret r2 in the context of this research. How large is this effect (small, medium, large)? 3. Make an statistical decision about the null using alpha =.05. Will you reject or retain the null based on your data? 4. Provide a conclusion of the data using Descriptive statistics and the context of the research.
Use the pulse rates in beats per minute (bpm) of a random sample of adult females listed in the data set available below to test the claim that the mean is less than 79 bpm. Use a 0.05 significance level. LOADING... Click the icon to view the pulse rate data. Assuming all conditions for conducting a hypothesis test are met, what are the null and alternative hypotheses? A. H0: μ=79 bpm H1: μ≠79 bpm B. H0: μ>79 bpm H1: μ<79 bpm C. H0: μ=79 bpm H1: μ<79 bpm D. H0: μ=79 bpm H1: μ>79 bpm Determine the test statistic. nothing (Round to two decimal places as needed.) Determine the P-value. nothing (Round to three decimal places as needed.) State the final conclusion that addresses the original claim. ▼ Reject Fail to reject H0. There is ▼ not sufficient sufficient evidence to conclude that the mean of the population of pulse rates for adult females is ▼ greater than not less than…
Select the most appropriate response. It is claimed that the mean age of bus drivers in Chicago is 59.3 years. If a hypothesis test is performed, how should you interpret a decision that fails to reject the null hypothesis? Question 2 options: There is not sufficient evidence to reject the claim µ = 59.3. There is sufficient evidence to reject the claim p = 59.3. There is not sufficient evidence to support the claim p = 59.3. There is sufficient evidence to support the claim u = 59.3.
Which of the following is the best decision and conclusion based on the result below? H.: p = 0.10 Ha:p + 0.10 Critical Value: +1.645 Computed Test Statistics: z = 5.61 O a. Since the computed test statistics is less than the critical value, do not reject Ho. Therefore, we conclude that at 0.10 level of significance, there is enough evidence that the population proportion is different from 10%. O b. Since the computed test statistics is less than the critical value, do not reject Ho. Therefore, we conclude that at 0.10evel of significance, there is enough evidence that the population proportion is different from 10%. O c. Since the computed test statistics is greater than the critical value, reject Ho. Therefore, we conclude that at 0.10 level of significance, there is enough evidence that the population proportion is different from 10%. O d. Since the computed test statistics is less than the critical value, reject Ho. Therefore, we conclude that at 0.10 level of significance, there…
The test statistic of z=2.29 is obtained when testing the claim that p≠0.418. a. Find the P-value. Using a significance level of α=0.10, should we reject H0 or should we fail to reject H0? a. P-value=____(Round to three decimal places as needed.)
11.10