a. System.out.println (x); for (int i -0; i < x.length - 1; i++) System.out.println (x); for (int i - 1; i < x.lengh; i++) System.out.println (x[i]); for (int i -0; i < x.length; i++) System.out.println (x[i]); None of the above 3. int [] x= new int[6]; To print all array elements we use: b. c. d. e.

a. System.out.println (x); for (int i -0; i < x.length - 1; i++) System.out.println (x); for (int i - 1; i < x.lengh; i++) System.out.println (x[i]); for (int i -0; i < x.length; i++) System.out.println (x[i]); None of the above 3. int [] x= new int[6]; To print all array elements we use: b. c. d. e.

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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IN HASKELL PROGRAMMING LANGUAGE PLEASE In case you do not know it: the game is played on a 3x3 grid that is initially empty. Two players are playing, by alternatingly making moves. A move by a player places their token (an X for player 1, an O for player 2) into a cell that was empty. We are using algebraic notations for indexing the positions in the board, with A,B,C indexing the columns and 1,2,3 the rows. Specifically, these coordinates would be used in the implementation for moves made by a human player. If the X X O Figure 1: Sample board position same token appears 3 times in any of the three columns, three rows or two main diagonals the game is over and that player wins. If the grid is filled without that happening the game is a draw. For the depicted board, we have Xs in positions C3 and A2, and an O in position B1. It would be O’s turn to make a move; a legal move would be C2, but it is not a good move, because X can force a win by responding A1. O cannot force a win, but…