// c) int sum = N; for (int i for (int j } } for } 0; i < 1000000; i++) { 1; j <= i; j++) { } for (int j 1; j <= i; j++) { sum += N; = sum += N; } = (int j sum += N; } cout << sum << endl; // d) vector list; for (int i = 1; i <= N * N; i++) { for (int j = 1; j <= N; j++) { list.push_back(i + j); 1; j <= i; j++) { = for (int i 1; i <= 2 * N; i++) { list.erase (list.begin() + list.size() - 1); } cout << "done!" << endl; answer: answer:
// c) int sum = N; for (int i for (int j } } for } 0; i < 1000000; i++) { 1; j <= i; j++) { } for (int j 1; j <= i; j++) { sum += N; = sum += N; } = (int j sum += N; } cout << sum << endl; // d) vector list; for (int i = 1; i <= N * N; i++) { for (int j = 1; j <= N; j++) { list.push_back(i + j); 1; j <= i; j++) { = for (int i 1; i <= 2 * N; i++) { list.erase (list.begin() + list.size() - 1); } cout << "done!" << endl; answer: answer:
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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(c) The answer is: N * 1000000 * (500000500000).
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