The average amount of time it takes for couples to further communicate with each other after their firstdate has ended is 3.03 days. Is this average different for blind dates? A researcher interviewed 55 coupleswho had recently been on blind dates and found that they averaged 2.7 days to communicate with eachother after the date was over. Their standard deviation was 0.943 days. What can be concluded at the a =0.10 level of significance?a. For this study, we should use Select an answerb. The null and alternative hypotheses would be:Ho: ? v Select an answer ✓H₁: ?vSelect an answer ✓(please show your answer to 3 decimal places.)(Please show your answer to 4 decimal places.)c. The test statistic?v=d. The p-value =e. The p-value is ? vaf. Based on this, we shouldg. Thus, the final conclusion is that ...Select an answer the null hypothesis.O The data suggest the population mean is not significantly different from 3.03 at a = 0.10, sothere is statistically significant evidence to conclude that the population mean time forcouples who have been on a blind date to communicate with each other after the date is overis equal to 3.03.O The data suggest the populaton mean is significantly different from 3.03 at a = 0.10, so thereis statistically significant evidence to conclude that the population mean time for couples whohave been on a blind date to communicate with each other after the date is over is differentfrom 3.03.O The data suggest that the population mean is not significantly different from 3.03 at a = 0.10,so there is statistically insignificant evidence to conclude that the population mean time forcouples who have been on a blind date to communicate with each other after the date is overis different from 3.03.Hint:Helpful Videos: Calculations [+] Setup [+] Interpretations [+]

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Answered: a. For this study, we should use Select…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A change is made that should improve student satisfaction with the parking situation at your school. Before the change, 37% of students approve of the parking that's provided. The null hypothesis Ho : p = 0.37 is tested against the alternative H.: p > 0.37 The given hypotheses are incorrect. What are the appropriate hypotheses for performing this significance test? Ho : p = 0.37; Ha :p> 0.37, where p= the true proportion of students that approve of the parking that's provided. Ho : p = 0.37; Ho : p + 0.37, where p= the true proportion of students that approve of the parking that's provided. Ho : p > 0.37; Họ : p = 0.37, where p= the true proportion of students that approve of the parking that's provided. Ho : p = 0.37; H, : p + 0.37, where p the sample proportion of students that approve of the parking that's provided. Ho : p > 0.37; Họ : p = 0.37, where p the sample proportion of students that approve of the parking that's provided.
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The commercial for the new Meat Man Barbecue claims that it takes 14 minutes for assembly. A consumer advocate thinks that the assembly time is lower than 14 minutes. The advocate surveyed 12 randomly selected people who purchased the Meat Man Barbecue and found that their average time was 13.5 minutes. The standard deviation for this survey group was 2.1 minutes. What can be concluded at the the a = 0.01 level of significance level of significance? You may assume the data are normally distributed.
Consider the hypothesis test below. Ho: P1 P2 ≤0 Ha : Pi-P2 > 0 The following results are for independent samples taken from the two populations. Sample 1 731= 100 P₁ = 0.24 Use pooled estimator of p. a. What is the p-value (to 4 decimals)? Use Table 1 from Appendix B. 0.0022 b. With a = 0.05, what is your hypothesis testing conclusion? Conclude the difference between the proportions is greater than 0 Sample 2 72 = 300 P₁ = 0.14
The average wait time to get seated at a popular restaurant in the city on a Friday night is 13 minutes. Is the mean wait time greater for men who wear a tie? Wait times for 11 randomly selected men who were wearing a tie are shown below. Assume that the distribution of the population is normal. 12, 13, 13, 15, 13, 11, 14, 13, 15, 11, 15 What can be concluded at the the a = 0.01 level of significance level of significance?
State the null and alternative hypotheses for the statistical test described below. Testing to see if there is evidence that a proportion is greater than 0.3. :: µ2 :: p : P1 :: P2 :: 0.3 :: x1 :: :: x2 :: P1 : P2 el :: Ho: i vs Ha: :: ::
1.Determine the test statistic. (Round to three decimal places as needed.) 2.Determine the P-value of the test statistic. (Round to four decimal places as needed.) 3. use 0.01 significance to test the claim
The average fruit fly will lay 394 eggs into rotting fruit. A biologist wants to see if the average will change for flies that have a certain gene modified. The data below shows the number of eggs that were laid into rotting fruit by several fruit flies that had this gene modified. Assume that the distribution of the population is normal. Round your mean and standard deviation to three decimal places when doing these calculations. 376, 400, 402, 362, 386, 400, 368, 391, 399, 407, 384, 384, 371, 371 Download CSV What can be concluded at the the a = 0.01 level of significance level of significance?
The average American consumes 85 liters of alcohol per year. Does the average college student consume less alcohol per year? A researcher surveyed 13 randomly selected college students and found that they averaged 82.1 liters of alcohol consumed per year with a standard deviation of 23 liters. What can be concluded at the the a = 0.10 level of significance? You may assume the data are normally distributed.
Before the furniture store began its ad campaign, it averaged 222 customers per day. The manager is investigating if the average is smaller since the ad came out. The data for the 14 randomly selected days since the ad campaign began is shown below. Round your mean and standard deviation to three decimal places when doing these calculations. 224, 211, 206, 206, 232, 189, 222, 197, 220, 210, 212, 213, 208, 189 Download CSV Assuming that the distribution is normal, what can be concluded at the a = 0.01 level of significance?
Only about 14% of all people can wiggle their ears. Is this percent lower for millionaires? Of the 400 millionaires surveyed, 40 could wiggle their ears. What can be concluded at the a = 0.10 level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Но: ? Select an answer V (please enter a decimal) H1: ? v Select an answer V (Please enter a decimal) c. The test statistic ? v (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 3 decimal places.) e. The p-value is ? v a f. Based on this, we should Select an answer g. Thus, the final conclusion is that ... the null hypothesis. O The data suggest the population proportion is not significantly lower than 14% at a = 0.10, so there is statistically insignificant evidence to conclude that the population proportion of millionaires who can wiggle their ears is lower than 14%. O The data suggest the populaton proportion is significantly lower…

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a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Ho: ? Select an answer ✓ H₁: ? Select an answer ✓ c. The test statistic?v= (please show your answer to 3 decimal places.)