Question 6Phases of TCP congestion control. Consider the figure below, which plots the evolution of TCP's congestionwindow at the beginning of each time unit (where the unit of time is equal to the RTT); see Figure 3.53 in thetext. In the abstract model for this problem, TCP sends a "flight" of packets of size cwnd at the beginning of eachtime unit. The result of sending that flight of packets is that either (i) all packets are ACKed at the end of the timeunit, (ii) there is a timeout for the first packet, or (iii) there is a triple duplicate ACK for the first packet.Congestion window size (in segments)403530252015105010 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39Time unit (in RTT)A. During which of the following intervals of time is TCP performing slow start*?B. During which of the following intervals of time is TCP performing congestion avoidance*?C. At the end of which units of time does TCP detect a triple-duplicate-ACK*?D.At the end of which unit(s) of time does TCP detect a loss via timeout*?

A. During which of the following intervals of time is TCP performing slow start*? B. During which of the following intervals of time is TCP performing congestion avoidance*? C. At the end of which units of time does TCP detect a triple-duplicate-ACK*?

A. During which of the following intervals of time is TCP performing slow start? B. During which of the following intervals of time is TCP performing congestion avoidance? C. At the end of which units of time does TCP detect a triple-duplicate-ACK*?

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Consider that only a single TCP (Reno) connection uses one 10Mbps link which does not buffer any data. Suppose that this link is the only congested link between the sending and receiving hosts. Assume that the TCP sender has a huge file to send to the receiver, and the receiver's receive buffer is much larger than the congestion window. We also make the following assumptions: each TCP segment size is 1,500 bytes; the two-way propagation delay of this connection is 150 msec; and this TCP connection is always in congestion avoidance phase, that is, ignore slow start. A. What is the maximum window size (in segments) that this TCP connection can achieve? B. What is the average window size (in segments) and average throughput (in bps) Of this TCP connection? C. How long would it take for this TCP connection to reach its maximum window again after recovering from a packet loss?
A TCP connection has been running for a long time and the value of cwnd = 22759. The MSS is the traditional value of 1460 (Ethernet payload minus the TCP and IP headers). Assume that a packet gets successfully ACKed and then a timeout occurs due to packet loss. What are the values of cwnd after each sequential event? (Apply the integer floor function here and always round down for all fractional values.) cwnd after ACK: cwnd after dropped packet:
Consider that only a single TCP (Reno) connection uses one 10Mbps link which does not buffer any data. Suppose that this link is the only congested link between the sending and receiving hosts. Assume that the TCP sender has a huge file to send to the receiver, and the receiver's receive buffer is much larger than the congestion window. We also make the following assumptions: each TCP segment size is 1,500 bytes; the two-way propagation delay of this connection is 150 msec; and this TCP connection is always in congestion avoidance phase, that is, ignore slow start. A. What is the maximum window size (in segments) that this TCP connection can achieve? B. What is the average window size (in segments) and average throughput (in bps) Of this TCP connection? C. How long would it take for this TCP connection to reach its maximum window again after recovering from a packet loss?
Dear Writer are you sure about the solution?I have this olution can you pleaae double check it? For each recognized segment in TCP slow start, the congestion window grows by one MSS. The congestion control method initiates a timeout and resets the congestion window to 1 MSS when all sent packets are lost. Yet, the threshold is also set to half of the current congestion window since the connection is still in the sluggish start phase. In order to obtain the slow start threshold, we must first determine the congestion window at the beginning of cycle 8 and then divide it by 2. One segment is transmitted and acknowledged in Round 1, and the congestion window is one MSS. Two segments are transmitted and acknowledged in Round 2, which has a congestion window of two MSS. In Round 3, 4 MSS of the congestion window is transmitted and acknowledged together with 4 segments. In Round 4, every packet that was sent is lost, therefore the congestion window is once again set to 1 MSS. Two segments…
Write a code in C that prints the following: Prints default TCP send and receive buffer sizes.Prints default UDP send and receive buffer sizes.Prints default SCTP send and receive buffer sizes.
After a timeout occurrence, we talked about doubling the timeout interval. Congestion control is achieved by the use of this method. Why does TCP require a window-based congestion-control method in addition to the doubling-timeoutinterval strategy?
Q1.Suppose a client, say C, has established a TCP connection with a server, say S. After establishing the connection, the sender sends two TCP messages with data back-to-back ( the first TCP message with sequence number 32 and the second TCP message with sequence number 100). a. What is the sequence number chosen by the client? What could be the reason for choosing this value of sequence number?b. What is the data size of first and second TCP data messages?c. Suppose the server receives the first and second TCP messages with data with the difference of 100 milliseconds delay. What could be the ACK number for both the TCP data messages from the server side as per the TCP RFC.
The text states that additive increase is a necessary condition for a congestion-control mechanism to be stable. Outline a specific instability that might arise if all increases were exponential; that is, if TCP continued to use slow start after CongestionWindow increased beyond Congestion Threshold.
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The following rule alerts on what protocol? alert tcp any any -> any 23 (msg:"TCP Mystery Protocol Testing Rule"; sid:1000003;) Group of answer choices FTP HTTP SSH Telnet
Dear Writer could oyu please kindly check my solution as well and let me know. if it is correct? For each recognized segment in TCP slow start, the congestion window grows by one MSS. The congestion control method initiates a timeout and resets the congestion window to 1 MSS when all sent packets are lost. Yet, the threshold is also set to half of the current congestion window since the connection is still in the sluggish start phase. In order to obtain the slow start threshold, we must first determine the congestion window at the beginning of cycle 8 and then divide it by 2. One segment is transmitted and acknowledged in Round 1, and the congestion window is one MSS. Two segments are transmitted and acknowledged in Round 2, which has a congestion window of two MSS. In Round 3, 4 MSS of the congestion window is transmitted and acknowledged together with 4 segments. In Round 4, every packet that was sent is lost, therefore the congestion window is once again set to 1 MSS. Two segments…