A. Determine the depth of the compression block. (mm) B.Determine the nominal moment strength (kN-m)

Q: The bell-crank mechanism is in equilibrium for an applied load of P = 35 kN. Assume that a = 240 mm,…

A: Given Data Determine the average shear stress in the pin-B.

Q: Determine the maximum bending stress and shear stress on the same section.

A: Bending moment  at the section B=Mb =90×0.2-20×0.2×0.1=1.4 kN-m=1.4×106 N-mm Moment of inertia,(I)…

Q: M kN-m ソー16m。 M= 1000 kN -m d: 36 ° y Find: T= Nオ kN Ax ニ A Ay: EN る の

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Q: Calculate the maximum tensile and compressive stresses in the section of BC of the beam. 15 ເຄດາ -…

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Q: *1-44. The 150-kg bucket is suspended from end E of the frame. If the diameters of the pins at A and…

A:

Q: *1-44. The 150-kg bucket is suspended from end E of the frame. If the diameters of the pins at A and…

A: Given : Weight of bucket = 150 kg Dia of pin A = 6mm Dia of pin D = 10 mm To Find : Average shear…

Q: (6) The tension member is fastened together using two bolts, one on each side of the member as…

A:

Q: For the truss and loading shown; a.) determine the force in all the truss members. 3 kN b.)mention…

A: Finding out forces in member.

Q: A wooden beam is fabricated from three boards, which are fastened together with screws, as shown.…

A: An object's bending stress is its normal stress when subjected to external loads at any…

Q: *1-44. The 150-kg bucket is suspended from end E of the frame. If the diameters of the pins at A and…

A:

Q: The frame is subjected to the load of 15 kN which acts on member ABD at D. Determine the required…

A:

Q: A frame ACD is supported by ball-and-socket joints at A and D and by a cable that passes through a…

A:

Q: 10 kN D 10 kN E F 6 m В L K J H 10 kN 6 panels at 4 m

A: To Find :- Force in member CJ

Q: Determine the vertical reactions at A, B, C, and D. Show complete solution

A:

Q: Q-A hollow shaft of external and internal diameters as 100 mm and 40 mm respectively is transmitting…

A: Given Internal diameter Di = 40 mm Outer Diameter Do =100 mm Number of revolution per minute N = 120…

Q: Determine the internal loadings at point C. There is a pin at A and B is a smooth support.

A: FInd reaction at A:∑ MB=0RA6-1263+33-631.5=0RA=10.5kn

Q: Determine RA at hinge and Rg at roller support.

A: RA+RB=100+10×6+10sin60o+0.5×6×20              =228.66 KN

Q: A simply supported rectangular concrete beam 6m long is reinforced with four-28mm diam  tension bars…

A:

Q: An I section girder or stanchion is constructed from two 80mm x 12mm flanges joined by an 80mm x…

A: I section girders: I sections girders are most commonly used in the construction of bridges. These…

Q: H.W No.1: The concrete I-beam of figure is pretensioned with four bounded stranded cables having…

A:

Q: 4-43 The center post B of the assembly has an original length of 124.7 mm, whereas posts A and C…

A: The normal stress at A(&C) and B is 189.315 MPa and 21.3675 MPa, respectively.Explanation:From…

Q: The beam CD is rigid and it rests on two posts as shown. Both posts are made of steel and have a…

A:

Q: An 8-ft deep gate AB shown in the figure is supported as shown. find the compression in the…

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Q: F9-5. The beam is subjected to the load at its end Determine the maximum principal stress at point…

A: Given : Determine the maximum principle stress at point B ? Concept -  Principle stresses are taken…

Q: 1-39 The lever is held to the fixed shaft using a tapered pin AB, which has a mean diameter of 6 mm.…

A: Given:Pin AB mean diameter,dm=6 mm

Q: 2. The bar AB is 2000 lb supported by a 5 ft 5 ft frictionless 10° inclined surface at A and 30°…

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Q: A A. The weight of the crate B. The internal force in rod AC 60° -60° C For the figure above, rods…

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Q: P6-5. Sketch the bending stress distribution over each cross section. (a) M P6-5 (b)

A: Two members cross section are shown in the above figure. We have to draw bending stress distribution…

Q: A horizontal beam AD with cross-section of 3800 mm² is supported by a wire at C and carries a load…

A:

Q: Lesson 1 1. A rigid frame is fabricated by joining the three bars with pins at B, C, and D, as…

A: The hinged support will have horizontal and vertical reaction. The roller support will have vertical…

Q: Asimply supported wood beam that is 13.5 m long carries a 36 kN concentrated load at B. The…

A: Given,  Length of the beam = 13.5m Load = 36KN OUR AIM IS TO DETERMINE THE FOLLOWING: 1.shear stress…

Q: 4-5 The A-36 steel rod is subjected to the loading shown. If the cross-sectional area of the rod is…

A: Displacement of b, δb​ =2.31 mmDisplacement of a, δa​ = 2.64 mmExplanation:

Q: a. Axial force on member marked with a in kN. b. Axial force on member marked with b in kN.

A: Axial Force in member a is 10.2 KN

Q: The field capacity of a soil is 35% by weight, and the wilting point is 15% by weight. If the dry…

A: Given data - Field Capacity of soil = 35% The wilting point is = 15% Dry bulk density of soil  1.25…

Q: A simply supported rectangular concrete beam 6m long is reinforced with four-28mm diam tension bars…

A: The values given in the question are as follows: Length of beam(L)=6 m Tension reinforcement=4-28 mm…

Q: T 2m 3 m B 10 kNE A 20 kN F 2 m2 m C D

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Q: Question-6b, A leaf spring is required to have a span of 2 .0 m. Determine the required thickness…

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Q: Three pulleys are joined by solid steel shafts AB and BC. If G = 200 GPa, determine the unit…

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Q: 1-7. Determine the resultant internal loading on the cross section through point D of the pliers.…

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Q: The bell-crank mechanism is in equilibrium for an applied load of F₁ = 13 kN applied at A. Assume a…

A: Given data,  F1 = 13 kN θ = 45° A = 310 mm B = 160 mm C = 80 mm

Q: Q 3: -Knowing that the bracket AB has a uniform thickness of in., determine (a) the principal planes…

A: As the point H is at the mid point of the given cross-section,  Therefore, σv=0

Q: Q 3: -Knowing that the bracket AB has a uniform thickness of in., determine (a) the principal planes…

A: The bracket is shown in the figure.

Q: A 3 470 B

A:

Braced cuts

The braced cut is a method of providing lateral support to the soil in foundation trenches, to prevent the trenches from deformation by the caving in of soil and resisting it from moving laterally. During shallow excavation in firm soil, generally, slopes are provided to resist the caving in of soil. During shallow excavation in soft soil and deep excavation, the chances of caving in of soil increase. Hence, it becomes necessary to make a provision to resist the deformation of trenches due to caving in of soil. The braced cut is the method used for such conditions. The excavation using braced cuts is a bit uneconomical as compared to the traditional open-cut excavation method but provides better safety than the cut excavation method.