a. Choose the item that correctly describes the oxidizing agent and the reducing agent in the reaction shown. Cr,O3(s) + 3CO(9) → 2Cr(s) + 3CO2 (9) C changes from oxidation number +4 to +2. The CO is the reducing agent. Cr changes from oxidation number +3 to 0. The Cr2O3 is the oxidizing agent. C changes from oxidation number +2 to +4. The CO is the reducing agent. Cr changes from oxidation number +3 to +2. The Cr2O3 is the oxidizing agent. C changes from oxidation number +2 to +4. The CO is the reducing agent. Cr changes from oxidation number +2 to +3. The Cr2O3 is the oxidizing agent. C changes from oxidation number +2 to +4. The CO is the reducing agent. Cr changes from oxidation number +3 to 0. The Cr2O3 is the oxidizing agent.
a. Choose the item that correctly describes the oxidizing agent and the reducing agent in the reaction shown. Cr,O3(s) + 3CO(9) → 2Cr(s) + 3CO2 (9) C changes from oxidation number +4 to +2. The CO is the reducing agent. Cr changes from oxidation number +3 to 0. The Cr2O3 is the oxidizing agent. C changes from oxidation number +2 to +4. The CO is the reducing agent. Cr changes from oxidation number +3 to +2. The Cr2O3 is the oxidizing agent. C changes from oxidation number +2 to +4. The CO is the reducing agent. Cr changes from oxidation number +2 to +3. The Cr2O3 is the oxidizing agent. C changes from oxidation number +2 to +4. The CO is the reducing agent. Cr changes from oxidation number +3 to 0. The Cr2O3 is the oxidizing agent.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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please explain what the answer is for both
Transcribed Image Text:b. Choose the item that correctly describes the oxidizing agent and the reducing agent in the reaction shown.
РbS(s) + 4H,О2(аaq) —> РЬSO, (s) + 4H,О()
S changes from oxidation number –2 to +6. The
PbS is the oxidizing agent.
O changes from oxidation number –1 to –2. The
H2O2 is the reducing agent.
S changes from oxidation number +2 to +6. The
PbS is the reducing agent.
O changes from oxidation number –1 to –2. The
H2O2 is the oxidizing agent.
S changes from oxidation number -2 to +4. The
PbS is the oxidizing agent.
O changes from oxidation number –1 to –2. The
H2O2 is the reducing agent.
S changes from oxidation number –2 to +6. The
PbS is the reducing agent.
O changes from oxidation number –1 to -2. The
H2O2 is the oxidizing agent.
Transcribed Image Text:a. Choose the item that correctly describes the oxidizing agent and the reducing agent in the reaction shown.
Cr,O3 (s) + 3C0(9) → 2Cr(s) + 3CO2 (g)
C changes from oxidation number +4 to +2. The
CO is the reducing agent.
Cr changes from oxidation number +3 to 0. The
Cr2 O3 is the oxidizing agent.
C changes from oxidation number +2 to +4. The
CO is the reducing agent.
Cr changes from oxidation number +3 to +2. The
Cr2O3 is the oxidizing agent.
C changes from oxidation number +2 to +4. The
CO is the reducing agent.
Cr changes from oxidation number +2 to +3. The
Cr2O3 is the oxidizing agent.
C changes from oxidation number +2 to +4. The
CO is the reducing agent.
Cr changes from oxidation number +3 to 0. The
Cr2 O3 is the oxidizing agent.
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