a.) C+ 2H2 = CH4 From the equations: 1. C+ 02= CO2 AH = -393.51 kJ 2. H2 + % O2 = H20 AH = -285.83 kJ 3. CH4 + 202 = CO2 +H2O AH = -890.37 kJ b.) 2N203 = 2N2 + 302 From the equations: 1. N203= NO + NO2 AH = 39.7 kJ 2. ½ N2 + ½ O2 = NO AH = 90.4 kJ 3. ½ N2 + O2 = NO2 AH = 33.8 kJ
a.) C+ 2H2 = CH4 From the equations: 1. C+ 02= CO2 AH = -393.51 kJ 2. H2 + % O2 = H20 AH = -285.83 kJ 3. CH4 + 202 = CO2 +H2O AH = -890.37 kJ b.) 2N203 = 2N2 + 302 From the equations: 1. N203= NO + NO2 AH = 39.7 kJ 2. ½ N2 + ½ O2 = NO AH = 90.4 kJ 3. ½ N2 + O2 = NO2 AH = 33.8 kJ
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![a.) C+ 2H2 = CH4
From the equations:
1. С + О23D СО2
AH = -393.51 kJ
2. H2 + % O2 = H20
AH = -285.83 kJ
3. CH4 + 202 = CO2 +H2O
AH = -890.37 kJ
b.) 2N203 = 2N2 + 302
From the equations:
1. N203= NO + NO2
AH = 39.7 kJ
2. ½ N2 + ½ O2 = NO
AH = 90.4 kJ
3. ½ N2 + O2 = NO2
AH = 33.8 kJ
%3D](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5468eb88-7349-4a33-9cb7-9f1cbc790b50%2F24ff6448-95c9-4048-9597-cf33038a0af0%2F4dn9b7_processed.png&w=3840&q=75)
Transcribed Image Text:a.) C+ 2H2 = CH4
From the equations:
1. С + О23D СО2
AH = -393.51 kJ
2. H2 + % O2 = H20
AH = -285.83 kJ
3. CH4 + 202 = CO2 +H2O
AH = -890.37 kJ
b.) 2N203 = 2N2 + 302
From the equations:
1. N203= NO + NO2
AH = 39.7 kJ
2. ½ N2 + ½ O2 = NO
AH = 90.4 kJ
3. ½ N2 + O2 = NO2
AH = 33.8 kJ
%3D
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