### Problem: Calculating Enthalpy (\( \Delta H \)) for Reaction To find \( \Delta H \) for the following reaction (Equation 4):\[ \text{NaOH}_{(s)} + \text{HCl}_{(g)} \rightarrow \text{NaCl}_{(s)} + \text{H}_2\text{O}_{(l)} \]### Given Reactions and Their Enthalpies:**Equation 1:**\[ \text{NaOH}_{(s)} + \text{HNO}_3{}_{(l)} \rightarrow \text{NaNO}_3{}_{(s)} + \text{H}_2\text{O}_{(l)} \quad \Delta H = -154.9 \text{ kJ/mol} \]**Equation 2:**\[ \text{HNO}_3{}_{(l)} + \text{AgCl}_{(s)} \rightarrow \text{HCl}_{(g)} + \text{AgNO}_3{}_{(s)} \quad \Delta H = +83.6 \text{ kJ/mol} \]**Equation 3:**\[ \text{NaCl}_{(s)} + \text{AgNO}_3{}_{(s)} \rightarrow \text{AgCl}_{(s)} + \text{NaNO}_3{}_{(s)} \quad \Delta H = -59.5 \text{ kJ/mol} \]To find \( \Delta H \) for Equation 4, the choices are:- Flip equation 1 only- Flip equation 2 only- Flip equation 3 only- Flip equation 1 and equation 2 only- Flip equation 1 and equation 3 only- Flip equation 2 and equation 3 only- Flip no equation**Screen Reader Version:**Consider the problem below:**Equation 1:**\[ \text{NaOH}_{(s)} + \text{HNO}_3{}_{(l)} \xrightarrow{} \text{NaNO}_3{}_{(s)} + \text{H}_2\text{O}_{(l)} \quad \Delta H = \text{minus } 154.9 \text{ kJ/mol} \]**Equation 2:**\[ \text{HNO}_3{}

---> NaNO3(s) + H201) AH = -154.9 kJ/mol ---> HCI9) + AGNO3(s) AH = +83.6 kJ/mol (Equation 1) NaOH(s) + HNO3(1) (Equation 2) HNO3() + AgCl(s) (Equation 3) NaCl(s) + A9NO3(s) (Equation 4) NaOH(s) + HCl(g) ) AgCl(s) + NaNO3(s) AH = -59.5 kJ/mol NaCls) + H2O0) AH = ??? ---> ---> To find AH for equation 4 you must: Screen Reader Version Consider the problem below: (Equation 1) N a O H(s) + HN O3(0) arrow N a N O3(s) + H2O1) AH (Equation 2) HN O3(1) + A gCls) arrow HCl(g) + A 9NO3(s) AH = +83.6 kJ/mol (Equation 3) N a Cl(s) + A GNO3(s): (Equation 4) N a O H(s) + HCl(g) ) arrow minus 154.9 kJ/mol arrow A gCl(s) + Na NO3(s) AH = minus 59.5 kJ/mol Na Cls) + H20) AH = ??? To find AH for equation 4 you must: flip equation 1 only flip equation 2 only flip equation 3 only flip equation 1 and equation 2 only flip equation 1 and equation 3 only O flip equation 2 and equation 3 only flip no equation

---> NaNO3(s) + H201) AH = -154.9 kJ/mol ---> HCI9) + AGNO3(s) AH = +83.6 kJ/mol (Equation 1) NaOH(s) + HNO3(1) (Equation 2) HNO3() + AgCl(s) (Equation 3) NaCl(s) + A9NO3(s) (Equation 4) NaOH(s) + HCl(g) ) AgCl(s) + NaNO3(s) AH = -59.5 kJ/mol NaCls) + H2O0) AH = ??? ---> ---> To find AH for equation 4 you must: Screen Reader Version Consider the problem below: (Equation 1) N a O H(s) + HN O3(0) arrow N a N O3(s) + H2O1) AH (Equation 2) HN O3(1) + A gCls) arrow HCl(g) + A 9NO3(s) AH = +83.6 kJ/mol (Equation 3) N a Cl(s) + A GNO3(s): (Equation 4) N a O H(s) + HCl(g) ) arrow minus 154.9 kJ/mol arrow A gCl(s) + Na NO3(s) AH = minus 59.5 kJ/mol Na Cls) + H20) AH = ??? To find AH for equation 4 you must: flip equation 1 only flip equation 2 only flip equation 3 only flip equation 1 and equation 2 only flip equation 1 and equation 3 only O flip equation 2 and equation 3 only flip no equation

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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