a). At 5% level of significance, is there evidence to support the board’s intention? Your conclusion must be in terms of the P-Value. Show all necessary work.
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Because of the increased cost of housing, a national real estate board wants to compare
the proportion of homeowners living in metropolitan areas with the proportion living in
rural areas. The board members know that housing costs are higher in metropolitan
areas, but they also know that small town and rural residents have substantially lower
income levels. The board has decided to find out whether the corresponding proportions
differ from one another. A random sample of 150 persons living in rural areas contains
93 homeowners, while a sample of 225 persons living in metropolitan areas has 126
homeowners.
a). At 5% level of significance, is there evidence to support the board’s intention? Your
conclusion must be in terms of the P-Value. Show all necessary work.
b). What type of error is possible and describe this error in terms of the problem?
c). Estimate the difference in the proportion of homeowners living in rural and
metropolitan areas using a 95% confidence interval. Show all necessary work. Using
this
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- A coach is interested in how many slam dunks the average college freshman at his university can do. Ten volunteers from the senior class step forward. After observing their performance, the coach concluded that college seniors can do an average of 10 slam dunks in a row without missing. what is the sample? what is the population?A contributor for the local newspaper is writing an article for the weekly fitness section. To prepare for the story, she conducts a study to compare the exercise habits of people who exercise in the morning to the exercise habits of people who work out in the afternoon or evening. She selects three different health centers from which to draw her samples. The 57 people she sampled who work out in the morning have a mean of 4.8 hours of exercise each week. The 56 people surveyed who exercise in the afternoon or evening have a mean of 4.2 hours of exercise each week. Assume that the weekly exercise times have a population standard deviation of 0.8 hours for people who exercise in the morning and 0.3 hours for people who exercise in the afternoon or evening. Let Population 1 be people who exercise in the morning and Population 2 be people who exercise in the afternoon or evening. Step 1 of 2 : Construct a 95% confidence interval for the true difference between the mean amounts…Thirty-seven percent of all Americans drink bottled water more than once a week (Natural resources Defense Council, December 4, 2015). Suppose you have been hired by the Natural Resources Defence Council to investigate bottled water consumption in St. Paul. You plan to select a sample of St. Paulites to estimate the proportion who drink bottled water more than once a week. Assume the popluation proportion of St. Paulites who drink bottled water more than once a week is 0.37, the same as the overall proportion of Americans who drink bottled water more than once a week. Use z-table. a. Suppose you select a sample of 540 St.Paulites. Show the sampling distribution of (to 4 decimals).E(p) = __________σ = _________ b. Based upon a sample of 540 St. Paulites, what is the probability that the sample proportion will be within 0.01 of the population proportion (to 4 decimals).probability = _________ c. Suppose you select a sample of 150 St.Paulites. Show the sampling distribution of p (to 4…
- According to a recent census, 15% of the people in the United States are of Hispanic origin. One county supervisor believes her county has a different proportion of Hispanic people than the nation as a whole. She looks at their most recent survey data, which was a random sample of 435 county residents, and found that 40 of those surveyed are of Hispanic origin. This is a one-proportion z test. Answer the following: A. ) The 435 residents were a random sample from the county of interest. The sample size is more than 100. One expects np0=(?) successes and nq0=(?) failures, which are both more than 10. B.) The 435 residents were a random sample from the county of interest. 435 is likely less than 10% of the population of a county. One expects np0=(?) successes and nq0=(?) failures, which are both more than 10. C.) The 435 residents were a random sample from the county of interest. The standard deviation of p is less than 0.5. One expects np0=(?) successes and…A J.D. Power and Associates vehicle quality survey asked new owners a variety of questions about their recently purchased automobile. One question asked for the owner's rating of the vehicle using categorical responses of average, outstanding, and exceptional. Another question asked for the owner's education level with the categorical responses some high school, high school graduate, some college, and college graduate. Assume the sample data below are for 500 owners who had recently purchased an automobile. Education Quality Rating Some HS HS Grad Some College College Grad Average 30 30 20 60 Outstanding 50 50 50 90 Exceptional 20 20 30 50 a. Use a 0.05 level of significance and a test of independence to determine if a new owner's vehicle quality rating is independent of the owner's education. Compute the value of the x test statistic (to 2 decimals). Use Table 3 of Appendix B to find the p-value. The p-value is - Select your answer - What is your conclusion? - Select your answer - v…The Wrigley Company, makers of Skittles candy, claims that they produce Skittles with the following distributions: 20% purple, 18% red, 14% yellow, 24% green, and 24% orange. You want to determine if the Wrigley Company’s claim for the proportion of yellow Skittles is correct. You randomly select a bag of plain Skittles from the grocery store shelf and count 15 yellow Skittles out of 71 total Skittles. a) Perform an appropriate hypotheses test at the 5% level, to determine if Wrigley’s claim for the proportion of yellow skittles is correct. b) Describe, in context, the ways you can increase power in your test from part a. c) Use your knowledge of confidence intervals to support the argument you found in part a.
- A newspaper infographic titled "Social Media Jeopardizing Your Job?" summarized data from a survey of 1,800 recruiters and human resource professionals. The infographic indicated that 51% of the people surveyed had reconsidered a job candidate based on his or her social media profile. Assume that the sample is representative of the population of recruiters and human resource professionals in the United States.Use the given information to estimate the proportion of recruiters and human resource professionals who have reconsidered a job candidate based on his or her social media profile using a 95% confidence interval. (Use a table or technology. Round your answers to three decimal places.)A pollster wishes to estimate the proportion of United States voters who favor capital punishment. How large a sample is needed in order to be 90% confident that the sample proportion will not differ from the true proportion by more than 5%?In the past, 26% of all homes with a stay-at-home parent, the father is the stay-at-home parent. An independent research firm has been charged with conducting a sample survey to obtain more current information. (a) What sample size your answer up to the nearest whole number.) needed if the research firm's goal is to estimate the current proportion homes with a stay-at-home parent in which the father is the stay-at-home parent with a margin of error of 0.04? Use a 95% confidence level. (Round (b) Repeat part (a) using a 99% confidence level. (Round your answer up to the nearest whole number.)
- A polling company conducted a survey of voters to obtain data for a political campaign. They selected 3500 voters randomly from the 16,800 names on the voter's registration lists of the country and found that 1365 intended to vote for candidate Doe. the sample proportion is?A controversial bill is being debated in the state legislature. Representative Williams wants to estimate within 2 percentage points and with 95% confidence the difference in the proportion of her male and female constituents who favor the bill. What sample size should she obtain? Group of answer choices a.n1 = n2 = 4802 b.n1 = n2 = 3383 c.n1 = n2 = 2401 d.n1 = n2 = 97A contributor for the local newspaper is writing an article for the weekly fitness section. To prepare for the story, she conducts a study to compare the exercise habits of people who exercise in the morning to the exercise habits of people who work out in the afternoon or evening. She selects three different health centers from which to draw her samples. The 56 people she sampled who work out in the morning have a mean of 4.4 hours of exercise each week. The 63 people surveyed who exercise in the afternoon or evening have a mean of 4.2 hours of exercise each week. Assume that the weekly exercise times have a population standard deviation of 0.8 hours for people who exercise in the morning and 0.7 hours for people who exercise in the afternoon or evening. Let Population 1 be people who exercise in the morning and Population 2 be people who exercise in the afternoon or evening. Step 1 of 2: Construct a 99% confidence interval for the true difference between the mean amounts of…
