a. A Gregorian telescope consists of a converging objective mirror of focal length 3-feet, with the converging secondary mirror 6 inches beyond the focal point of the primary. The secondary focuses starlight at the vertex of the primary and the real image is viewed by an eyepiece (converging lens) of focal length 4 inches. Find the focal length of the secondary mirror and the angular magnification of the telescope. Hint: Angular magnification M = where e is the angle of the incident ray through the vertex of the objective and e" is the angle of a ray through the vertex of the eyepiece of the final image. It is easier to draw and analyze the geometry if you replace the converging mirrors with converging lenses. pnimary secm dary eyeprece b. Show that if the system matrix M ( D) is written for an arbitrary optical system and C = 0, then D gives the angular magnification of the system. %3D c. Evaluate the system matrix for the Gregorian telescope described in part (a), and check that C = 0 and D is the same value you calculated previously.
a. A Gregorian telescope consists of a converging objective mirror of focal length 3-feet, with the converging secondary mirror 6 inches beyond the focal point of the primary. The secondary focuses starlight at the vertex of the primary and the real image is viewed by an eyepiece (converging lens) of focal length 4 inches. Find the focal length of the secondary mirror and the angular magnification of the telescope. Hint: Angular magnification M = where e is the angle of the incident ray through the vertex of the objective and e" is the angle of a ray through the vertex of the eyepiece of the final image. It is easier to draw and analyze the geometry if you replace the converging mirrors with converging lenses. pnimary secm dary eyeprece b. Show that if the system matrix M ( D) is written for an arbitrary optical system and C = 0, then D gives the angular magnification of the system. %3D c. Evaluate the system matrix for the Gregorian telescope described in part (a), and check that C = 0 and D is the same value you calculated previously.
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