A Z-test for single population mean is conducted with Ha: µ < 10, at significance level of 0.05, The most significant result is suggested by the following test statistic O-4.5 O 2.2 O 4.7 O 3.7 O -1.65 O 1.96
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- Suppose the mean height of women age 20 years or older in a certain country is 62.2 inches. One hundred randomly selected women in a certain city had a mean height of 61.7 inches. At the 1% significance level, do the data provide sufficient evidence to conclude that the mean height of women in the city differs from the national mean? Assume that the population standard deviation of the heights of women in the city is 3.9 inches. Set up the hypotheses for the one-mean z-test. H0: μ (≠, >, <, =) ________ppmHa: μ (≠, >, <, =) _________ppm Compute the value of the test statistic.z=__________(Round to two decimal places as needed.) Determine the critical value(s). Select the correct choice below and fill in the answer box within your choice. (Round to two decimal places as needed.) A. The critical value is zα=____________ B. The critical values are ±zα/2=±____________ C. The critical value is −zα=___________A random sample of 100 pumpkins is obtained and the mean circumferenceis found to be 40.5 cm and standard deviation 1.6 cm. Use a 0.05 significance level to test the claim that the mean circumference of all pumpkins is equal to 39.9 cm.8. 140 migrating pigeons were caught by a biologist for data collection. The mass of these pigeons is normally distributed with mean 0.9 kg and standard deviation of deviation 0.15 kg. a) Determine the percentile rank of a pigeon weighing 1kg. b) What proportions of pigeons have weight greater than 1.1 kg or less than 0.7 Kg 31
- 5) A sample of 400 male students is found to have a mean height (55 + 18) inches. Can it be reasonably regarded as a sample from a large population with mean height 66 inches and standard deviation 1.30 inches? Test at 5% level of significance.An ANOVA is used to evaluate the mean difference among three treatment conditions with a sample of n= 12 particpantsin each treatment. For study, what is df total?Determine the critical value for a right tailed test of a population mean at the a=0.001 level of significance with 15 degrees of fredom.
- In a test of weight loss programs, 111 subjects were divided such that 37 subjects followed each of 3 diets. Each was weighed a year after starting the diet and the results are in the ANOVA table below. Use a 0.05 significance level to test the claim that the mean weight loss is the same for the different diets. Source of Variation Between Groups Within Groups Total P-value 25.38918 0.8127 0.446353 F crit 3.080387 df MS F 50.778 3373.977 3424.755 2 108 31.24053 110 Should the null hypothesis that all the diets have the same mean weight loss be rejected? O A. Yes, because the P-value is greater than the significance level. O B. No, because the P-value is greater than the significance level. OC. No, because the P-value is less than the significance level. O D. Yes, because the P-value is less than the significance level.In its Fuel Economy Guide for 2016 model vehicles, the Environmental Protection Agency provides data on 11701170 vehicles. There are a number of high outliers, mainly hybrid gas‑electric vehicles. If we ignore the vehicles identified as outliers, however, the combined city and highway gas mileage of the other 11461146 vehicles is approximately Normal with mean 23.0 miles per gallon (mpg) and standard deviation 4.9 mpg. The quartiles of any distribution are the values with cumulative proportions 0.25 and 0.75 They span the middle half of the distribution. What is the first quartile of the distribution of gas mileage? What is the third quartile of the distribution of gas mileage?One important consideration in determining which location is best for a new retail business is the amount of traffic that passes the location each business day. Counters are placed at each of four locations on the five weekdays, and the number of cars passing each location is recorded in the table below. At 0.05 level of significance, is there sufficient evidence of a significant difference in the mean number of cars per day at the four locations?Using MS Excel,what is the computed value of the F statistic ? * Location II II IV 45 48 44 39 50 60 50 49 39 40 38 39 44 45 42 40 42 43 44 43 0.76 2.23 1.19 0.84
- A random sample of 100 recorded deaths in United States during the past year showed that an average lifespan of 70.8 years. Assuming a population standard deviation of 8.7 years, does this deem to indicate that the mean lifespan today is greater than 70 years? Use a 0.05 level of significance.In an automobile repair and service industry, the average number of defective items in all the lots of automobile parts produced by a machine last week was 8. The supervisor believes that the mean number of defective parts produced by the same machine will differ in the present week. To test whether the average differs from 8, he samples 30 lots to obtain the mean number of defective parts to be 9 with a standard deviation of 3.Using the critical value approach, identify the decision at the 5% level of significance. Group of answer choices The decision is not to reject H0 because the test statistic does not fall in the rejection region (-∞,-1.960] U [1.960, ∞). The decision is to reject H0 because the test statistic falls in the rejection region (-∞,-1.645]. The decision is not to reject H0 because the test statistic does not fall in the rejection region [1.645, ∞). The decision is not to reject H0 because the test statistic does not fall in the rejection region (-∞,-1.645] U…Please answer the last three parts of this question.