(Ungraded) C Language - Write a program that takes in a year and determines whether that year is a leap year. ---### Leap Year Determination in the Gregorian CalendarA year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are:1. The year must be divisible by 42. If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400; therefore, both 1700 and 1800 are not leap years.Some example leap years are 1600, 1712, and 2016.#### Example Inputs and Outputs- If the input is 1712, the output is: ``` 1712 - leap year ```- If the input is 1913, the output is: ``` 1913 - not a leap year ```#### Program ExampleBelow is an example program written in C, which takes in a year and determines whether that year is a leap year.```c#include #include int main(void) { int inputYear; bool isLeapYear = false; scanf("%d", &inputYear); /* Type your code here. */ return 0;}```In this program:- `#include ` and `#include ` are directives to include the standard input-output and boolean libraries respectively.- `int main(void)` is the main function where the program starts execution.- `int inputYear;` declares an integer variable `inputYear` to hold the year input.- `bool isLeapYear = false;` initializes a boolean variable `isLeapYear` to false.- `scanf("%d", &inputYear);` reads the input year from the user.The actual logic to determine whether `inputYear` is a leap year should be typed where it says `/* Type your code here. */`.---This transcription includes all necessary details for understanding the leap year concept and a basic example of how to implement a leap year check programmatically.

Here's the algorithm for the provided code:1. Declare the necessary variables:inputYear: to store…

A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are: 1) The year must be divisible by 4 2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400; therefore, both 1700 and 1800 are not leap years Some example leap years are 1600, 1712, and 2016. Write a program that takes in a year and determines whether that year is a leap year. Ex: If the input is 1712, the output is: 1712 leap year Ex: If the input is 1913, the output is: 1913 not a leap year 1 #include 2 #include 3 4 int main(void) { 5 6 7 8 9 10 11 12} int inputYear; bool isLeapYear = false; scanf("%d", &inputYear); /* Type your code here. */ return 0;

A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are: 1) The year must be divisible by 4 2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400; therefore, both 1700 and 1800 are not leap years Some example leap years are 1600, 1712, and 2016. Write a program that takes in a year and determines whether that year is a leap year. Ex: If the input is 1712, the output is: 1712 leap year Ex: If the input is 1913, the output is: 1913 not a leap year 1 #include 2 #include 3 4 int main(void) { 5 6 7 8 9 10 11 12} int inputYear; bool isLeapYear = false; scanf("%d", &inputYear); /* Type your code here. */ return 0;

C++ Programming: From Problem Analysis to Program Design

8th Edition

ISBN:9781337102087

Author:D. S. Malik

Publisher:D. S. Malik

Chapter8: Arrays And Strings

Section: Chapter Questions

Problem 10PE

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Question: A common year in the modern Gregorian Calendar consists of 365 days. In reality, Earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are: 1) The year must be divisible by 4 2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400 Some example leap years are 1600, 1712, and 2016. Write a program that takes in a year and determines the number of days in February for that year. My Code: def days_in_feb(user_year): is_leap_year = 29 not_leap_year = 28 if user_year % 4 ==0: return is_leap_year elif user_year % 4 ==0 and user_year % 100 == 0 and user_year % 400 == 0: return is_leap_year else: return(not_leap_year) if __name__ == '__main__': # Type your code here. Your code must call the function. user_year =…
A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are: 1) The year must be divisible by 4 2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400 Some example leap years are 1600, 1712, and 2016. Write a program that takes in a year and determines whether that year is a leap year. Ex: If the input is: 1712 the output is: 1712 - leap year Ex: If the input is: 1913 the output is: 1913 - not a leap year
A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are: 1) The year must be divisible by 4 2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400 Some example leap years are 1600, 1712, and 2016. Write a program that takes in a year and determines whether that year is a leap year. Ex: If the input is 1712, the output is: 1712 - leap year Ex: If the input is 1913, the output is: 1913 - not a leap year I need answer in CC+
A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are: 1) The year must be divisible by 4 2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400; therefore, both 1700 and 1800 are not leap years Some example leap years are 1600, 1712, and 2016. Write a program that takes in a year and determines whether that year is a leap year. Ex: If the input is 1712, the output is: 1712 - leap year Ex: If the input is 1913, the output is: 1913 - not a leap year
A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are: 1) The year must be divisible by 4 2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400 Some example leap years are 1600, 1712, and 2016. Write a program that takes in a year and determines whether that year is a leap year. Ex: If the input is: 1712 output: 1712 is a leap year. input: 1913 output: 1913 is not a leap year. My Code: def is_leap_year(user_year):if((user_year % 4 == 0 and user_year % 100 != 0) or (user_year % 400 == 0)):print("{} is a leap year.".format(user_year))else:print("{} is not a leap year.".format(user_year))return is_leap_year if __name__ == '__main__':user_year =…
A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are: 1) The year must be divisible by 4 2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400 Some example leap years are 1600, 1712, and 2016. Write a program that takes in a year and determines whether that year is a leap year. Ex: If the input is: 1712 output: 1712 is a leap year. input: 1913 output: 1913 is not a leap year. My Code: def is_leap_year(user_year):if (user_year%4 == 0) and (user_year%100 != 0):print('{} is a leap year.'.format(user_year))elif user_year == 0:print('{} is not a leap year.'.format(user_year))elif user_year%400 == 0:print('{} is a leap year.'.format(user_year))else: print('{} is not a leap…
A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are: 1) The year must be divisible by 4 2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400 Some example leap years are 1600, 1712, and 2016. Write a program that takes in a year and determines whether that year is a leap year. Ex: If the input is: 1712 the output is: 1712 is a leap year. Ex: If the input is: 1913 the output is: 1913 is not a leap year. Your program must define and call the following function. The function should return true if the input year is a leap year and false otherwise.def is_leap_year(user_year) Note: This is a lab from a previous chapter that now requires the use of a function. def…
A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are: 1) The year must be divisible by 4 2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400 Some example leap years are 1600, 1712, and 2016. Write a program that takes in a year and determines whether that year is a leap year. Ex: If the input is: 1712 output: 1712 is a leap year. input: 1913 output: 1913 is not a leap year. Your program must define and call the following function. The function should return true if the input year is a leap year and false otherwise.def is_leap_year(user_year) My Code: def is_leap_year(user_year):if((user_year % 4 == 0 and user_year % 100 != 0) or (user_year % 400 == 0)):print("{} is a leap…
A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are: 1) The year must be divisible by 4 2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400 Some example leap years are 1600, 1712, and 2016. Write a program that takes in a year and determines whether that year is a leap year. Ex: If the input is: 1712 output: 1712 is a leap year. input: 1913 output: 1913 is not a leap year. Your program must define and call the following function. The function should return true if the input year is a leap year and false otherwise.def is_leap_year(user_year) My Code: def is_leap_year(user_year):if((user_year % 4 == 0 and user_year % 100 != 0) or (user_year % 400 == 0)):print("{} is a leap…
A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are: 1) The year must be divisible by 4 2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400 Some example leap years are 1600, 1712, and 2016. Write a program that takes in a year and determines whether that year is a leap year. Ex: If the input is: 1712 the output is: 1712 is a leap year. Ex: If the input is: 1913 the output is: 1913 is not a leap year. Your program must define and call the following function. The function should return True if the input year is a leap year or False otherwise.def is_leap_year(user_year)
A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are: 1) The year must be divisible by 4 2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400; therefore, both 1700 and 1800 are not leap years Some example leap years are 1600, 1712, and 2016. Write a program that takes in a year and determines whether that year is a leap year. Ex: If the input is 1712, the output is: 1712 - leap year Ex: If the input is 1913, the output is: 1913 - not a leap year #include <stdio.h> #include <stdbool.h> int main(void) { int inputYear; bool isLeapYear = false; scanf("%d", &inputYear); /* Type your code here. */ return 0; }