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A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are: 1) The year must be divisible by 4 2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400; therefore, both 1700 and 1800 are not leap years Some example leap years are 1600, 1712, and 2016. Write a program that takes in a year and determines whether that year is a leap year. Ex: If the input is 1712, the output is: 1712 leap year Ex: If the input is 1913, the output is: 1913 not a leap year 1 #include 2 #include 3 4 int main(void) { 5 6 7 8 9 10 11 12} int inputYear; bool isLeapYear = false; scanf("%d", &inputYear); /* Type your code here. */ return 0;

A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are: 1) The year must be divisible by 4 2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400; therefore, both 1700 and 1800 are not leap years Some example leap years are 1600, 1712, and 2016. Write a program that takes in a year and determines whether that year is a leap year. Ex: If the input is 1712, the output is: 1712 leap year Ex: If the input is 1913, the output is: 1913 not a leap year 1 #include 2 #include 3 4 int main(void) { 5 6 7 8 9 10 11 12} int inputYear; bool isLeapYear = false; scanf("%d", &inputYear); /* Type your code here. */ return 0;

C++ Programming: From Problem Analysis to Program Design
C++ Programming: From Problem Analysis to Program Design
8th Edition
ISBN:9781337102087
Author:D. S. Malik
Publisher:D. S. Malik
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(Ungraded) C Language - Write a program that takes in a year and determines whether that year is a leap year.

--- ### Leap Year Determination in the Gregorian Calendar A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are: 1. The year must be divisible by 4 2. If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400; therefore, both 1700 and 1800 are not leap years. Some example leap years are 1600, 1712, and 2016. #### Example Inputs and Outputs - If the input is 1712, the output is: ``` 1712 - leap year ``` - If the input is 1913, the output is: ``` 1913 - not a leap year ``` #### Program Example Below is an example program written in C, which takes in a year and determines whether that year is a leap year. ```c #include <stdio.h> #include <stdbool.h> int main(void) { int inputYear; bool isLeapYear = false; scanf("%d", &inputYear); /* Type your code here. */ return 0; } ``` In this program: - `#include <stdio.h>` and `#include <stdbool.h>` are directives to include the standard input-output and boolean libraries respectively. - `int main(void)` is the main function where the program starts execution. - `int inputYear;` declares an integer variable `inputYear` to hold the year input. - `bool isLeapYear = false;` initializes a boolean variable `isLeapYear` to false. - `scanf("%d", &inputYear);` reads the input year from the user. The actual logic to determine whether `inputYear` is a leap year should be typed where it says `/* Type your code here. */`. --- This transcription includes all necessary details for understanding the leap year concept and a basic example of how to implement a leap year check programmatically.
Transcribed Image Text:--- ### Leap Year Determination in the Gregorian Calendar A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are: 1. The year must be divisible by 4 2. If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400; therefore, both 1700 and 1800 are not leap years. Some example leap years are 1600, 1712, and 2016. #### Example Inputs and Outputs - If the input is 1712, the output is: ``` 1712 - leap year ``` - If the input is 1913, the output is: ``` 1913 - not a leap year ``` #### Program Example Below is an example program written in C, which takes in a year and determines whether that year is a leap year. ```c #include <stdio.h> #include <stdbool.h> int main(void) { int inputYear; bool isLeapYear = false; scanf("%d", &inputYear); /* Type your code here. */ return 0; } ``` In this program: - `#include <stdio.h>` and `#include <stdbool.h>` are directives to include the standard input-output and boolean libraries respectively. - `int main(void)` is the main function where the program starts execution. - `int inputYear;` declares an integer variable `inputYear` to hold the year input. - `bool isLeapYear = false;` initializes a boolean variable `isLeapYear` to false. - `scanf("%d", &inputYear);` reads the input year from the user. The actual logic to determine whether `inputYear` is a leap year should be typed where it says `/* Type your code here. */`. --- This transcription includes all necessary details for understanding the leap year concept and a basic example of how to implement a leap year check programmatically.
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