A woman bails out of an airplane at an altitude of 12,000 t, falls freely for 24 s, then opens her parachute. How long will it take her to reach the ground? Assume linear air resistance v R/s, taking p=0.15 without the parachute and p=1.5 with the parachute. (Suggestion: First determine her height above the ground and velocity when the parachute opens.) It will take her 402 seconds to reach the ground (Round to the nearest whole number as needed) dave Ch

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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A woman bails out of an airplane at an altitude of 12,000 ft, falls freely for 24 s, then opens hier parachute. How long will it take her to reach the ground? Assume linear air resistance v
K-
ft/s, taking p=0.15 without the parachute and p=1.5 with the parachute. (Suggestion: First determine her height above the ground and velocity when the parachute opens.)
It will take her 402 seconds to reach the ground
(Round to the nearest whole number as needed)
dave
Transcribed Image Text:A woman bails out of an airplane at an altitude of 12,000 ft, falls freely for 24 s, then opens hier parachute. How long will it take her to reach the ground? Assume linear air resistance v K- ft/s, taking p=0.15 without the parachute and p=1.5 with the parachute. (Suggestion: First determine her height above the ground and velocity when the parachute opens.) It will take her 402 seconds to reach the ground (Round to the nearest whole number as needed) dave
x(34) = 12000 - 322 (24) + - - (0+ ³.2.3) (1---15-24)
x(24)=8240.0078
2831
v(24)= (6 + 322) 15-24 32.3
e
IS
v(24)=-208.80117424
●
0=(8740...) - (²23²) + + + s (-20...+ 2222²2) (1 ²56)
0=(8240)-(21.46666)-124.8896717155533(1-¹9
0=(8240...)-(21.4.) - (124...) + (124...e-1.st)
0=8115.118156594447-(21.4..)t +(124...e-1.st)
Transcribed Image Text:x(34) = 12000 - 322 (24) + - - (0+ ³.2.3) (1---15-24) x(24)=8240.0078 2831 v(24)= (6 + 322) 15-24 32.3 e IS v(24)=-208.80117424 ● 0=(8740...) - (²23²) + + + s (-20...+ 2222²2) (1 ²56) 0=(8240)-(21.46666)-124.8896717155533(1-¹9 0=(8240...)-(21.4.) - (124...) + (124...e-1.st) 0=8115.118156594447-(21.4..)t +(124...e-1.st)
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