A wire is placed at right angles (0 = 90.0°) to the lines of magnetic flux between the poles of a horseshoe magnet. The length of the wire in the field is 78.0 mm and the field strength is 0.910 T. If the current in the wire is 4.10 A: (a) Calculate the force on the wire, giving your answer in newtons (N) to 3 significant figures. Force when - 90.0⁰: N (b) If the wire is rotated so that it is 30.0° to the magnetic field, calculate the new force, giving your answer in newtons (N) to 3 significant figures. Force when 0 = 30.0°: N

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ISBN:9781305952300
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Chapter1: Units, Trigonometry. And Vectors
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A wire is placed at right angles (0 = 90.0°) to the lines of magnetic flux between the poles of a
horseshoe magnet. The length of the wire in the field is 78.0 mm and the field strength is 0.910 T. If the
current in the wire is 4.10 A:
(a) Calculate the force on the wire, giving your answer in newtons (N) to 3 significant figures.
Force when = 90.0°:
N
(b) If the wire is rotated so that it is 30.0° to the magnetic field, calculate the new force, giving your
answer in newtons (N) to 3 significant figures.
Force when 0 = 30.0°:
N
Transcribed Image Text:A wire is placed at right angles (0 = 90.0°) to the lines of magnetic flux between the poles of a horseshoe magnet. The length of the wire in the field is 78.0 mm and the field strength is 0.910 T. If the current in the wire is 4.10 A: (a) Calculate the force on the wire, giving your answer in newtons (N) to 3 significant figures. Force when = 90.0°: N (b) If the wire is rotated so that it is 30.0° to the magnetic field, calculate the new force, giving your answer in newtons (N) to 3 significant figures. Force when 0 = 30.0°: N
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