**Transcription of Educational Content:****Context:**You are aiming to construct a 99% confidence interval to estimate the population mean price of milk (per gallon) in your city. A random sample of prices from different stores has been selected, with a mean of $3.66 and a standard deviation of $0.20.**Questions:****(a)** What is the best point estimate, based on the sample, to use for the population mean?\[ \_\_\_\_\_ \text{ dollars} \]**(b)** For each of the following sampling scenarios, determine which distribution should be used to calculate the critical value for the 99% confidence interval for the population mean.*(In the table, $ Z $ refers to a standard normal distribution, and $ t $ refers to a $ t $ distribution.)***Table:**| Sampling Scenario | $ Z $ | $ t $ | Could Use Either $ Z $ or $ t $ | Unclear ||-----------------------------------------------------------------------------------|---------|---------|-------------------------------------|---------|| The sample has size 17, and it is from a normally distributed population with a known standard deviation of 0.26. | $ \bigcirc $ | | | || The sample has size 80, and it is from a non-normally distributed population. | | $ \bigcirc $ | | || The sample has size 13, and it is from a normally distributed population with an unknown standard deviation. | | $ \bigcirc $ | | |In this table, for each scenario, a circle indicates which statistical distribution is appropriate for use based on the characteristics of the sample and the population from which it is drawn.

Answered: Image /qna-images/answer/e3f0306e-90c3-4ac3-8a56-2f2a2ed92064.jpg

Answered: (a) What is the best point estimate,…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Consider the sample data 2, 4, and 6 with population standard deviation of 1.633. Compute the following using the formulas in Central Limit Theorem. N=3 n=2 sample mean sample standard deviation Choose... sample variance Choose... + Please answer all parts of the question.
In order to estimate the average amount a customer spends on a meal in a major restaurant, data was collected from a sample of 30 customers. Suppose the population standard deviation is $3 . If the sample mean is $22, what is the 95% confidence interval for the population mean? Select one: a. [20.93 , 23.07] b. [20.59 , 23.41] c. [21.99 , 22.01] d. [20.95 , 23.05]
Women are recommended to consume 1790 calories per day. You suspect that the average calorie intake is smaller for women at your college. The data for the 15 women who participated in the study is shown below: 1959, 1908, 1789, 1544, 1805, 1656, 1899, 1811, 1686, 1688, 1687, 1943, 1612, 1789, 1467 Assuming that the distribution is normal, what can be concluded at the α = 0.05 level of significance? For this study, we should use The null and alternative hypotheses would be: H0: H1: The test statistic = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is α Based on this, we should the null hypothesis. Thus, the final conclusion is that ... The data suggest the population mean is not significantly less than 1790 at α = 0.05, so there is sufficient evidence to conclude that the population mean calorie intake for women at your college is equal to 1790. The data suggest the populaton…
If, in a sample of n=16 selected from a normal population, X=60 and S=12, what are the critical values of t if the level of significance, α, is 0.01, the null hypothesis, H0, is μ=50, and the alternative hypothesis, H1, is μ≠50? Click here to view page 1 of the critical values for the t Distribution. LOADING... Click here to view page 2 of the critical values for the t Distribution. LOADING... Question content area bottom Part 1 The critical values of t are enter your response here.
Is the difference between the mean annual salaries of entry level architects in Denver, Colorado, and Lincoln, Nebraska, equal to $10,500? To decide, you select a random sample of entry level architects from each city. The results of each survey are shown. Assume the population standard deviations are o₁ =$6511 and 2 = $6192. At a = 0.01, what should you conclude? Entry level architects Entry level architects in Denver, CO x₁ = 58,300 n₁ = 39 In Lincoln, NE x2 = 54,240 n2 = 30 What are the null and alternative hypotheses for this test? OA. Ho: H₁₂ = 10,500 Ha: H₁-H2*10,500 OD. Ho: P₁-H2>10,500 Ha: H1-H₂s 10,500 Calculate the standardized test statistic. z= (Round to two decimal places as needed.) Determine the P-value. The P-value is (Round to three decimal places as needed.) What can you conclude about the data? OB. Ho: H1 H2S 10,500 Ha H1-H2>10,500 OC. Ho: H1 H2210,500 Ha H1-H2 <10,500 OE. Ho: H1 H2*10,500 Ha: 1-2=10,500 OA. Reject Ho. At the 1% level of significance, there is…
ACT scores are normally distributed with mean 22 and standard deviation 4.7. A random sample of 32 MiSU students has a mean ACT of 23.6. A. Estimate the mean ACT score for all MiSU students at the 95% confidence level. B. If we want to estimate the mean ACT score for all MiSU students at the 99% confidence level with a margin of error of 10, then what sample size will we need?
14. The sales price of a specific brand of cereal is believed to be normally distributed. Data were collected for a sample of 16 boxes of that brand of cereal. If the sample mean is 2 OMR and the sample standard deviation is 0.4 OMRthen the 90% confidence interval for the population mean is A. (1.8355 , 2.1645) B. (1.8040 , 2.1960) C. None D. (1.8247 , 2.1753)
Assume that all grade-point averages are to be standardized on a scale between 0 and 6. How many grade-point averages must be obtained so that the sample mean is within 0.012 of the population mean? Assume that a 95% confidence level is desired. If using the range rule of thumb, σ can be estimated as range/4=6−0/4=1.5. Does the sample size seem practical?
Answer these question
1. Find the sample standard deviation from the following data. 1420,1223,988,694,730,836,721,742,541,623,1449,950 2., Construct a 99%confidence interval for the population mean μ.

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