(a) What is capacitance? You are given a parallel-plate capacitor with vacuum between them, now if you replace the vacuum (K=1) by other dielectric material with K value is more than one, then how will the capacitance change? explain on the basis of polarization. (b) In Fig. 1, two parallel-plate capacitors (with air between the plates) are connected to a battery. Capacitor 1 has a plate area of 1.5 cm? and an electric field (between its plates) of magnitude 2000 V/m. Capacitor 2 has a plate area of 0.70 cm? and an electric field of magnitude 1500 V/m. What is the total C2 Figure 1 charge on the two capacitors?

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(a) What is capacitance? You are given a parallel-plate capacitor with vacuum between
them, now if you replace the vacuum (K=1) by other dielectric material with K value is
more than one, then how will the capacitance change? explain on the basis of
polarization.
(b) In Fig. 1, two parallel-plate capacitors (with air between the
plates) are connected to a battery. Capacitor 1 has a plate area
of 1.5 cm? and an electric field (between its plates) of
magnitude 2000 V/m. Capacitor 2 has a plate area of 0.70 cm?
and an electric field of magnitude 1500 V/m. What is the total
C2
Figure 1
charge on the two capacitors?
Transcribed Image Text:(a) What is capacitance? You are given a parallel-plate capacitor with vacuum between them, now if you replace the vacuum (K=1) by other dielectric material with K value is more than one, then how will the capacitance change? explain on the basis of polarization. (b) In Fig. 1, two parallel-plate capacitors (with air between the plates) are connected to a battery. Capacitor 1 has a plate area of 1.5 cm? and an electric field (between its plates) of magnitude 2000 V/m. Capacitor 2 has a plate area of 0.70 cm? and an electric field of magnitude 1500 V/m. What is the total C2 Figure 1 charge on the two capacitors?
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