A wall of length "L" m and height "H" m is made from a thick bricklayer of 26 cm with thermal conductivity of 0.55 W/mk is subjected to heat transfer due to the outside temperature as 43 °C and inside temperature 24 °C. If the energy loss is 10680 kJ in 9 hours. Determine the Heat transfer rate, Surface Area and Length and Height of the wall, if L = 1.5 H. Solution: i) Heat Transfer Rate (in Joule/Sec) = 329.62962962963 ii) Surface Area of the Wall (in m?) = 8.2013113592061 iii) Height of the Wall (H in m) = 2.3382773373014 iv) Length of the Wall (L in m) = 3.5074160059521

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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A wall of length "L" m and height "H" m is made from a thick bricklayer of 26 cm with thermal conductivity
of 0.55 W/mk is subjected to heat transfer due to the outside temperature as 43 °C and inside
temperature 24 °C. If the energy loss is 10680 kJ in 9 hours.
Determine the Heat transfer rate, Surface Area and Length and Height of the wall, if L = 1.5 H.
Solution:
i) Heat Transfer Rate (in Joule/Sec) =
329.62962962963
ii) Surface Area of the Wall (in m?) =
8.2013113592061
i) Height of the Wall (H in m) =
2.3382773373014
iv) Length of the Wall (L in m) =
3.5074160059521
Transcribed Image Text:A wall of length "L" m and height "H" m is made from a thick bricklayer of 26 cm with thermal conductivity of 0.55 W/mk is subjected to heat transfer due to the outside temperature as 43 °C and inside temperature 24 °C. If the energy loss is 10680 kJ in 9 hours. Determine the Heat transfer rate, Surface Area and Length and Height of the wall, if L = 1.5 H. Solution: i) Heat Transfer Rate (in Joule/Sec) = 329.62962962963 ii) Surface Area of the Wall (in m?) = 8.2013113592061 i) Height of the Wall (H in m) = 2.3382773373014 iv) Length of the Wall (L in m) = 3.5074160059521
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