A W16×67 of A992 steel has two holes in each flange for 7/8-inch-diameter bolts. For A992 steel: Fy = 50 ksi, F₁ = 65 ksi. For a W16×67: bƒ = 10.2 in., tf = 0.665 in., Zx =130 in.3 and S = 117 in.3 a. Assuming continuous lateral support, verify that the holes must be accounted for and determine the nominal flexural strength. (Express your answer to three significant figures.) Mn = ft-kips b. What is the percent reduction in strength? (Express your answer to three significant figures.) % Reduction =

Steel Design (Activate Learning with these NEW titles from Engineering!)
6th Edition
ISBN:9781337094740
Author:Segui, William T.
Publisher:Segui, William T.
Chapter5: Beams
Section: Chapter Questions
Problem 5.12.2P
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A W16×67 of A992 steel has two holes in each flange for 7/8-inch-diameter bolts.
For A992 steel: Fy
= 50 ksi, F₁ = 65 ksi.
For a W16×67: bƒ
=
10.2 in., tf
= 0.665 in., Zx =130 in.3 and S
= 117 in.3
a. Assuming continuous lateral support, verify that the holes must be accounted for and determine the nominal flexural strength.
(Express your answer to three significant figures.)
Mn
=
ft-kips
b. What is the percent reduction in strength?
(Express your answer to three significant figures.)
%
Reduction =
Transcribed Image Text:A W16×67 of A992 steel has two holes in each flange for 7/8-inch-diameter bolts. For A992 steel: Fy = 50 ksi, F₁ = 65 ksi. For a W16×67: bƒ = 10.2 in., tf = 0.665 in., Zx =130 in.3 and S = 117 in.3 a. Assuming continuous lateral support, verify that the holes must be accounted for and determine the nominal flexural strength. (Express your answer to three significant figures.) Mn = ft-kips b. What is the percent reduction in strength? (Express your answer to three significant figures.) % Reduction =
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